Preparing for IBPS PO, SBI PO, RBI Assistant, LIC AAO, SSC CGL, RRB NTPC, or any other competitive exam? This comprehensive practice set contains 100 original Profit and Loss questions designed at a moderate difficulty level to match the latest banking exam pattern.
Each question includes a step-by-step solution, shortcut method, and exam tip to help you improve both accuracy and calculation speed. The questions progress from basic to moderate level, making this collection suitable for beginners as well as serious aspirants.
Practice these questions regularly to strengthen your concepts, master important Profit and Loss formulas, and boost your confidence for the Quantitative Aptitude section of competitive exams.
Profit and Loss Formulas for Competitive Exams
📘 Important Profit and Loss Formulas
Before solving Profit and Loss questions, it’s important to understand the basic formulas. These formulas are frequently used in banking, SSC, railway, insurance, and other competitive examinations.
1. Profit
Profit = Selling Price (SP) − Cost Price (CP)
Use this formula when the selling price is greater than the cost price.
2. Loss
Loss = Cost Price (CP) − Selling Price (SP)
Use this formula when the selling price is less than the cost price.
3. Profit Percentage
Profit % = (Profit ÷ Cost Price) × 100
Remember: Profit percentage is always calculated on the Cost Price.
4. Loss Percentage
Loss % = (Loss ÷ Cost Price) × 100
Loss percentage is also calculated on the Cost Price.
5. Selling Price
If Profit is given:
Selling Price = Cost Price + Profit
If Loss is given:
Selling Price = Cost Price − Loss
6. Selling Price Using Percentage
If Profit % is given:
SP = CP × (100 + Profit%) ÷ 100
If Loss % is given:
SP = CP × (100 − Loss%) ÷ 100
7. Cost Price
If Profit % is given:
CP = (SP × 100) ÷ (100 + Profit%)
If Loss % is given:
CP = (SP × 100) ÷ (100 − Loss%)
8. Marked Price
Marked Price (MP) = Selling Price × 100 ÷ (100 − Discount%)
This formula is useful when the Selling Price and Discount are known.
9. Discount
Discount = Marked Price − Selling Price
10. Discount Percentage
Discount % = (Discount ÷ Marked Price) × 100
11. Selling Price After Discount
SP = MP × (100 − Discount%) ÷ 100
12. Marked Price After Markup
MP = CP × (100 + Markup%) ÷ 100
13. Successive Discount
Net Discount = A + B − (A × B ÷ 100)
Example:
20% and 10%
Net Discount = 20 + 10 − 2 = 28%
14. Effective Cost Price
Effective Cost Price = Purchase Cost + Transportation + Labour + Packaging + Insurance + Repair + Other Expenses
Always include additional expenses while calculating profit or loss.
15. No Profit, No Loss
When:
Cost Price = Selling Price
then
Profit = 0 and Loss = 0
16. Profit on Selling Price
If Profit Percentage is calculated on the Selling Price:
Profit % = (Profit ÷ Selling Price) × 100
Read the question carefully to identify whether the percentage is based on the Cost Price or the Selling Price.
17. Loss on Selling Price
If Loss Percentage is calculated on the Selling Price:
Loss % = (Loss ÷ Selling Price) × 100
This type of question is less common but occasionally appears in competitive exams
18. Relationship Between Profit and Loss
- If Selling Price > Cost Price, there is Profit.
- If Selling Price < Cost Price, there is Loss.
- If Selling Price = Cost Price, there is No Profit, No Loss.
💡 Quick Revision Tips
- Profit and Loss percentages are generally calculated on the Cost Price, unless the question states otherwise.
- Never ignore transportation, packaging, labour, repair, or insurance charges. These increase the Effective Cost Price.
- Do not add successive discounts directly. Always use the successive discount formula.
- In percentage-based questions, assuming Cost Price = ₹100 often makes calculations much faster.
- Practice these formulas regularly to improve both speed and accuracy in competitive examinations.
Table of Contents
📌 Question 1
📝 Question
A trader purchases an article at 20% below its marked price. He spends an additional ₹360 on transportation and packaging. He then marks the article 50% above his effective cost and allows two successive discounts of 10% and 20% on the marked price. If he finally earns a profit of ₹1,080, find the original purchase price of the article.
⚡ Shortcut Method
Let original purchase price = ₹x
Marked Price = x ÷ 0.80 = 1.25x
Effective CP = x + 360
Final SP
= (x + 360) × 1.50 × 0.90 × 0.80
= 1.08(x + 360)
Since profit = ₹1,080:
SP = x + 1,080
Therefore,
1.08(x + 360) = x + 1,080
1.08x + 388.8 = x + 1,080
0.08x = 691.2
x = ₹8,640
✅ Final Answer
₹8,640
📌 Question 2
📝 Question
A merchant purchases 100 articles at the same cost price per article. He sells 30% of the articles at a profit of 20%, 40% of the articles at a profit of 10%, and the remaining articles at a selling price of ₹1,540 each. If his overall profit is 20%, find the cost price per article.
⚡ Shortcut Method
Let the cost price per article be ₹x.
There are 100 articles:
- 30 articles sold at 20% profit → SP = 30 × 1.20x = 36x
- 40 articles sold at 10% profit → SP = 40 × 1.10x = 44x
- Remaining 30 articles sold at ₹1,540 each → SP = 30 × 1,540 = ₹46,200
Overall profit = 20%, so total SP = 120% of total CP:
Total CP = 100x
Total SP = 120x
Therefore,
36x + 44x + 46,200 = 120x
80x + 46,200 = 120x
46,200 = 40x
x = ₹1,155
✅ Final Answer
₹1,155 per article
📌 Question 3
📝 Question
A dishonest dealer buys goods at ₹100 per kg. When purchasing, he uses a faulty scale that shows 1,000 g when he actually takes 1,100 g for the same price. When selling, he marks his goods 20% above his nominal cost price and uses a false weight of 800 g instead of 1 kg. Find his overall actual profit percentage.
⚡ Shortcut Method
Let’s solve it carefully by taking 1 kg as the nominal unit.
⭐ Shortcut Method
At the time of purchase:
He pays ₹100 for a scale reading of 1,000 g, but actually receives 1,100 g.
So, actual cost of 1 kg:
₹100 × 1000/1100 = ₹90.91
At the time of selling:
He marks the nominal cost price 20% above ₹100:
Selling price for a nominal 1 kg =
₹100 × 120% = ₹120
But he gives only 800 g while charging ₹120.
Therefore, actual selling price per 1 kg:
₹120 × 1000/800 = ₹150
Actual Profit %
Profit = ₹150 − ₹90.91 = ₹59.09
Profit % = (59.09 / 90.91) × 100
= 65%
✅ Final Answer
65% Actual Profit
📌 Question 4
📝 Question
A shopkeeper marks an article 60% above its cost price. He offers a discount of 20% and then an additional discount of x% on the reduced price. Even after both discounts, he earns a profit of 12%. Find x.
⚡ Shortcut Method
Assume CP = ₹100
MP = ₹160
After 20% discount:
160 × 0.80 = ₹128
Required SP for 12% profit = ₹112
Therefore,
128 × (100 − x)% = 112
(100 − x)% = 112/128
= 87.5%
x = 12.5%
✅ Final Answer
12.5%
📌 Question 5
📝 Question
A trader buys two machines for a total of ₹1,20,000. He sells the first machine at a 20% profit and the second at a 10% loss. If the selling price of the first machine is ₹18,000 more than that of the second machine, find the cost price of each machine.
⚡ Shortcut Method
Let CP of first machine = ₹x
CP of second = ₹1,20,000 − x
Selling prices:
First = 1.20x
Second = 0.90(1,20,000 − x)
Difference = ₹18,000
1.20x − 0.90(1,20,000 − x) = 18,000
1.20x − 1,08,000 + 0.90x = 18,000
2.10x = 1,26,000
x = ₹60,000
Second CP = ₹60,000
✅ Final Answer
First Machine = ₹60,000
Second Machine = ₹60,000
📌 Question 6
📝 Question
A trader purchased 400 electric kettles at ₹1,500 each. He spent ₹30,000 on transportation and ₹10,000 on insurance. During transit, 20 kettles were damaged and sold at 40% of their effective cost price. The remaining 380 kettles were sold at a 25% profit on their effective cost price, with an online marketplace deducting a 4% commission on their selling price. Find the trader’s overall profit percentage.
⚡ Shortcut Method
Let’s calculate it carefully.
⭐ Shortcut Method
1. Total effective cost
Purchase cost:
400 × ₹1,500 = ₹6,00,000
Additional expenses:
₹30,000 + ₹10,000 = ₹40,000
Total effective cost:
₹6,00,000 + ₹40,000 = ₹6,40,000
So, effective cost per kettle:
₹6,40,000 ÷ 400 = ₹1,600
2. Damaged 20 kettles
They are sold at 40% of effective cost:
SP per damaged kettle = 40% of ₹1,600 = ₹640
SP from 20 kettles:
20 × ₹640 = ₹12,800
3. Remaining 380 kettles
They are sold at 25% profit on effective cost:
SP per kettle = 125% of ₹1,600 = ₹2,000
Gross SP:
380 × ₹2,000 = ₹7,60,000
Marketplace commission = 4% of ₹7,60,000:
= ₹30,400
Net SP:
₹7,60,000 − ₹30,400 = ₹7,29,600
4. Total actual SP
= ₹12,800 + ₹7,29,600
= ₹7,42,400
Profit:
₹7,42,400 − ₹6,40,000 = ₹1,02,400
Therefore,
Profit % = (₹1,02,400 ÷ ₹6,40,000) × 100
= 16%
✅ Final Answer
16% Overall Profit
📌 Question 7
📝 Question
A retailer marks an article 80% above its cost price. He offers a discount of 15%, followed by another discount of x%. Even after both discounts, he earns a 22.4% profit. Find the value of x.
⚡ Shortcut Method
Assume CP = ₹100
MP = ₹180
Required SP = 122.4% of ₹100
= ₹122.40
After 15% discount:
180 × 85%
= ₹153
Therefore,
153 × (100 − x)% = 122.40
(100 − x)% = 122.40 ÷ 153
= 80%
Therefore,
x = 20%
✅ Final Answer
20%
📌 Question 8
📝 Question
A trader purchases two types of laptops. He buys 40 laptops of Type A at ₹30,000 each and 60 laptops of Type B at ₹20,000 each. He sells 25% of Type A laptops at a 20% profit and 50% of Type B laptops at a 12% loss. The remaining laptops of both types are sold at the same selling price per laptop. If the trader earns an overall profit of 15%, find the selling price of each remaining laptop.
⚡ Shortcut Method
Total CP
= (40 × 30,000) + (60 × 20,000)
= ₹24,00,000
Required total SP
= 24,00,000 × 115%
= ₹27,60,000
Type A sold at 20% profit:
= 10 × 30,000 × 120%
= ₹3,60,000
Type B sold at 12% loss:
= 30 × 20,000 × 88%
= ₹5,28,000
SP already received
= 3,60,000 + 5,28,000
= ₹8,88,000
Required SP from remaining 60 laptops
= 27,60,000 − 8,88,000
= ₹18,72,000
Selling price per remaining laptop
= 18,72,000 ÷ 60
= ₹31,200
✅ Final Answer
₹31,200 per laptop
📌 Question 9
📝 Question
A dishonest wholesaler buys sugar at ₹48 per kg but uses a 900 g weight while purchasing. While selling, he uses an 800 g weight and charges his customers for 1 kg at ₹52. Find his actual profit percentage.
⚡ Shortcut Method
For ₹48, he actually receives 900 g.
Cost of 1 kg actually obtained
= 48 ÷ 0.9
= ₹53.33
While selling, he gives only 800 g for ₹52.
Actual SP per kg
= 52 ÷ 0.8
= ₹65
Profit %
= (65 − 53.33) ÷ 53.33 × 100
= 21.875%
✅ Final Answer
21.875% Profit
📌 Question 10
📝 Question
A wholesaler purchases 600 office chairs at ₹2,400 each. He spends ₹60,000 on transportation and ₹30,000 on insurance. During transportation, 30 chairs are damaged and sold at 40% of their effective cost price. Of the remaining chairs, 120 are sold at a loss of 5%, while the rest are sold through an agent charging 5% commission on the selling price. If the wholesaler earns an overall profit of 18%, find the selling price of each chair sold through the agent.
⚡ Shortcut Method
Effective CP
= 600 × 2,400 + 60,000 + 30,000
= ₹15,30,000
Effective CP per chair
= 15,30,000 ÷ 600
= ₹2,550
Required total SP
= 15,30,000 × 118%
= ₹18,05,400
Damaged chairs’ SP
= 30 × 2,550 × 40%
= ₹30,600
120 chairs’ SP
= 120 × 2,550 × 95%
= ₹2,90,700
Required net SP from remaining 450 chairs
= 18,05,400 − 30,600 − 2,90,700
= ₹14,84,100
Let their selling price = ₹x each.
After 5% commission:
450 × x × 95% = 14,84,100
x = 14,84,100 ÷ 427.5
= ₹3,471.58
✅ Final Answer
₹3,471.58 per chair
📌 Question 11
📝 Question
A distributor purchases 400 air purifiers at ₹1,500 each. He spends ₹20,000 on transportation and ₹10,000 on insurance. During transportation, 20 air purifiers are damaged and sold at 40% of their effective cost price. The remaining units are sold at 20% profit on the effective cost price, but an online marketplace deducts 5% commission on the selling price. Find the distributor’s overall profit percentage.
⚡ Shortcut Method
Effective CP
= 400 × 1,500 + 20,000 + 10,000
= ₹6,30,000
Effective CP per unit
= 6,30,000 ÷ 400
= ₹1,575
Damaged units’ SP
= 20 × 1,575 × 40%
= ₹12,600
Remaining units’ net SP
= 380 × 1,575 × 120% × 95%
= ₹6,82,290
Total SP
= 6,82,290 + 12,600
= ₹6,94,890
Profit
= 6,94,890 − 6,30,000
= ₹64,890
Profit %
= 64,890 ÷ 6,30,000 × 100
= 10.30%
✅ Final Answer
10.30% Profit
📌 Question 12
📝 Question
A retailer marks an article 60% above its cost price. He first offers a 20% discount and then an additional discount of x% on the reduced price. Even after both discounts, he earns a 12% profit. Find the value of x.
⚡ Shortcut Method
Assume CP = ₹100
MP = ₹160
After 20% discount:
160 × 80% = ₹128
Required SP for 12% profit
= ₹112
Therefore,
128 × (100 − x)% = 112
(100 − x)% = 112/128
= 87.5%
Therefore,
x = 12.5%
✅ Final Answer
12.5%
📌 Question 13
📝 Question
A trader purchases 40 laptops of Type A at ₹1,500 each and 40 laptops of Type B at ₹1,800 each. He sells 20% of Type A laptops at a 25% profit and 20% of Type B laptops at a 10% loss. The remaining laptops of both types are sold at the same price per laptop. If the trader earns an overall profit of 15%, find the selling price of each remaining laptop.
⚡ Shortcut Method
Total CP
= 40 × 1,500 + 40 × 1,800
= ₹1,32,000
Required total SP
= 1,32,000 × 115%
= ₹1,51,800
SP of 8 Type A laptops
= 8 × 1,500 × 125%
= ₹15,000
SP of 8 Type B laptops
= 8 × 1,800 × 90%
= ₹12,960
SP already received
= 15,000 + 12,960
= ₹27,960
Remaining laptops
= 80 − 16
= 64
Required SP from remaining laptops
= 1,51,800 − 27,960
= ₹1,23,840
SP per laptop
= 1,23,840 ÷ 64
= ₹1,935
✅ Final Answer
₹1,935 per laptop
📌 Question 14
📝 Question
A dishonest wholesaler purchases sugar at ₹240 per kg but uses a 800 g weight while purchasing, thereby receiving only 800 g for every kilogram paid for. While selling, he uses a 900 g weight and charges ₹330 for every kilogram according to his stated measurement. Find his actual profit percentage.
⚡ Shortcut Method
Actual cost of 1 kg received
= 240 ÷ 0.80
= ₹300
Actual SP per kg
= 330 ÷ 0.90
= ₹366.67
Profit
= 366.67 − 300
= ₹66.67
Profit %
= 66.67 ÷ 300 × 100
= 22.22%
✅ Final Answer
22.22% Profit
📌 Question 15
📝 Question
A wholesaler purchases 1,000 smart speakers at ₹500 each and incurs ₹50,000 on transportation, insurance, and packaging.
Out of the total stock:
- 80 speakers are damaged and sold at 50% of their effective cost price.
- 150 speakers are sold at a 5% loss during a clearance sale.
- The remaining speakers are sold through an online marketplace charging 5% commission on the selling price.
If the wholesaler earns an overall profit of 18%, find the selling price of each remaining speaker before commission.
⚡ Shortcut Method
Effective CP
= 1,000 × 500 + 50,000
= ₹5,50,000
Effective CP per speaker
= ₹550
Required total SP
= 5,50,000 × 118%
= ₹6,49,000
Damaged speakers’ SP
= 80 × 550 × 50%
= ₹22,000
Clearance-sale SP
= 150 × 550 × 95%
= ₹78,375
Required net SP from remaining speakers
= 6,49,000 − 22,000 − 78,375
= ₹5,48,625
Remaining speakers
= 1,000 − 80 − 150
= 770
After 5% commission:
770 × SP × 95% = 5,48,625
SP = 5,48,625 ÷ 731.5
= ₹750
✅ Final Answer
₹750 per speaker
📌 Question 16
📝 Question
A trader purchases 300 printers at ₹800 each and 200 scanners at ₹1,100 each. He spends ₹25,000 on transportation and insurance.
He sells 100 printers at a 15% profit and 50 scanners at a 10% loss. The remaining printers and scanners are sold at the same selling price per item.
If his overall profit is 20%, find the selling price of each remaining item.
⚡ Shortcut Method
Total Effective CP
= 300 × 800 + 200 × 1,100 + 25,000
= ₹4,85,000
Required Total SP
= 4,85,000 × 120%
= ₹5,82,000
SP of 100 printers
= 100 × 800 × 115%
= ₹92,000
SP of 50 scanners
= 50 × 1,100 × 90%
= ₹49,500
SP required from remaining 350 items
= 5,82,000 − 92,000 − 49,500
= ₹4,40,500
SP per remaining item
= 4,40,500 ÷ 350
= ₹1,258.57
✅ Final Answer
₹1,258.57 per item
📌 Question 17
📝 Question
A manufacturer incurs an additional expense equal to 10% of the purchase cost of an article. He then marks the article 80% above the resulting effective cost price and offers successive discounts of 15% and 10%. After the sale, a payment gateway deducts 4% of the billed amount as a processing charge.
Find his overall profit percentage.
⚡ Shortcut Method
Assume Purchase CP = ₹100
After additional expense:
= 100 × 110%
= ₹110
Marked Price
= 110 × 180%
= ₹198
After discounts:
198 × 85% × 90%
= ₹151.47
After 4% processing charge:
151.47 × 96%
= ₹145.4112
Profit
= 145.4112 − 110
= ₹35.4112
Profit %
= 35.4112 ÷ 110 × 100
= 32.19%
✅ Final Answer
32.19% Profit
📌 Question 18
📝 Question
A dishonest trader purchases a commodity at ₹200 per kg but uses a 850 g weight instead of 1 kg while purchasing. While selling, he uses a 750 g weight instead of 1 kg and charges ₹230 for every kilogram according to his stated measurement.
Find his actual profit percentage.
⚡ Shortcut Method
Actual cost of 1 kg received:
= 200 ÷ 0.85
= ₹235.294
Actual SP per kg:
= 230 ÷ 0.75
= ₹306.667
Profit %
= (306.667 − 235.294) ÷ 235.294 × 100
= 30.33%
✅ Final Answer
30.33% Profit
📌 Question 19
📝 Question
A trader purchases two machines for a total of ₹1,80,000. He sells the first machine at a 30% profit and the second at a 20% loss. The total selling price obtained is ₹14,000 less than what he would have received if both machines had been sold at a 25% profit. Find the cost price of each machine.
⚡ Shortcut Method
If both were sold at 25% profit:
Required SP
= 1,80,000 × 125%
= ₹2,25,000
Actual total SP
= 2,25,000 − 14,000
= ₹2,11,000
Let CP of first machine = ₹x.
CP of second = ₹1,80,000 − x
Actual SP:
1.30x + 0.80(1,80,000 − x)
= 2,11,000
1.30x + 1,44,000 − 0.80x
= 2,11,000
0.50x = 67,000
x = ₹1,34,000
Second machine CP
= 1,80,000 − 1,34,000
= ₹46,000
✅ Final Answer
First Machine = ₹1,34,000
Second Machine = ₹46,000
📌 Question 20
📝 Question
A wholesaler purchases 1,000 smart speakers at ₹1,200 each and incurs ₹40,000 on transportation, insurance, and packaging.
Out of the stock:
- 50 speakers are damaged and sold at 40% of their effective cost price.
- 100 speakers are sold at a 5% loss during a clearance sale.
- The remaining speakers are sold through an online marketplace at ₹1,700 each, from which the platform deducts 6% commission.
Find the wholesaler’s overall profit percentage.
⚡ Shortcut Method
Let the effective cost per speaker include transportation, insurance, and packaging.
⭐ Shortcut Method
1. Total Effective Cost
Purchase cost:
1,000 × ₹1,200 = ₹12,00,000
Additional expenses = ₹40,000
Total effective cost:
₹12,00,000 + ₹40,000 = ₹12,40,000
Effective CP per speaker:
₹12,40,000 ÷ 1,000 = ₹1,240
2. Damaged 50 speakers
Sold at 40% of effective CP:
SP per speaker = 40% of ₹1,240 = ₹496
SP = 50 × ₹496 = ₹24,800
3. Clearance sale — 100 speakers
Sold at 5% loss:
SP per speaker = 95% of ₹1,240
= ₹1,178
SP = 100 × ₹1,178
= ₹1,17,800
4. Remaining 850 speakers
Remaining = 1,000 − 50 − 100 = 850
Gross SP:
850 × ₹1,700 = ₹14,45,000
Marketplace commission = 6%:
₹14,45,000 × 6% = ₹86,700
Net SP:
₹14,45,000 − ₹86,700
= ₹13,58,300
5. Total Actual Selling Price
= ₹24,800 + ₹1,17,800 + ₹13,58,300
= ₹15,00,900
Total CP = ₹12,40,000
Profit:
₹15,00,900 − ₹12,40,000
= ₹2,60,900
Therefore,
Profit % = (₹2,60,900 ÷ ₹12,40,000) × 100
= 21.04% approximately
✅ Final Answer
21.04% Overall Profit
📚 Recommended Reading
- Profit and Loss Questions Series
- Percentage Questions with Answers
- Ratio and Proportion Questions with Answers
📌 Question 21
📝 Question
A trader purchases an electronic device for ₹5,000 and incurs additional expenses equal to 10% of the purchase price. He marks the device 60% above the effective cost price and offers successive discounts of 20% and 10%. Find his profit percentage.
⚡ Shortcut Method
Assume Purchase CP = ₹100
Additional expenses = 10%
Effective CP = ₹110
Marked Price
= 110 × 160%
= ₹176
After successive discounts:
SP = 176 × 80% × 90%
= ₹126.72
Profit
= 126.72 − 110
= ₹16.72
Profit %
= 16.72 ÷ 110 × 100
= 15.2%
✅ Final Answer
15.2% Profit
📌 Question 22
📝 Question
A dishonest trader buys a commodity at ₹240 per kg, but uses a false weight that gives him 25% more goods than the quantity for which he pays (i.e., he receives 1,250 g for every 1,000 g he pays for). While selling, he uses a 960 g weight instead of 1 kg and charges ₹324 for every kilogram according to his stated measurement. Find his actual profit percentage.
⚡ Shortcut Method
Let’s calculate the actual cost and selling price per kg carefully.
⭐ Shortcut Method
1. Actual Cost Price
He pays ₹240 for 1,000 g, but actually receives 1,250 g.
So his actual cost for 1 kg is:
₹240 × 1000 / 1250
= ₹192 per kg
2. Actual Selling Price
He charges ₹324 for a stated 1 kg, but actually gives only 960 g.
So for every actual 1 kg, his selling proceeds are:
₹324 × 1000 / 960
= ₹337.50 per kg
3. Actual Profit
Profit = ₹337.50 − ₹192
= ₹145.50
Profit %:
= (₹145.50 ÷ ₹192) × 100
= 75.78125%
✅ Final Answer
75.78% Actual Profit
📌 Question 23
📝 Question
A trader purchases two machines for a total of ₹2,00,000. He sells the first machine at a 30% profit and the second at a 15% loss. If his overall profit is 12%, find the cost price of each machine.
⚡ Shortcut Method
Required total SP
= 2,00,000 × 112%
= ₹2,24,000
Let CP of first machine = ₹x.
Second machine CP = ₹2,00,000 − x
Therefore,
1.30x + 0.85(2,00,000 − x) = 2,24,000
1.30x + 1,70,000 − 0.85x = 2,24,000
0.45x = 54,000
x = ₹1,20,000
Second CP
= 2,00,000 − 1,20,000
= ₹80,000
✅ Final Answer
First Machine = ₹1,20,000
Second Machine = ₹80,000
📌 Question 24
📝 Question
A wholesaler purchases 500 smart watches at ₹1,000 each and spends ₹70,000 on transportation, insurance, and packaging.
Out of the stock:
- 20 watches are damaged and sold at 50% of their effective cost price.
- 80 watches are sold at a 10% loss.
- The remaining watches are sold through an agent who charges 5% commission on the selling price.
If the wholesaler earns an overall profit of 18%, find the selling price per remaining watch before commission.
⚡ Shortcut Method
Effective CP
= 500 × 1,000 + 70,000
= ₹5,70,000
Effective CP per watch
= 5,70,000 ÷ 500
= ₹1,140
Required total SP
= 5,70,000 × 118%
= ₹6,72,600
Damaged watches’ SP
= 20 × 1,140 × 50%
= ₹11,400
80 watches sold at 10% loss:
= 80 × 1,140 × 90%
= ₹82,080
Remaining watches
= 500 − 20 − 80
= 400
Required net SP from remaining watches
= 6,72,600 − 11,400 − 82,080
= ₹5,79,120
Since the agent keeps 5%:
400 × SP × 95% = 5,79,120
SP = 5,79,120 ÷ 380
= ₹1,524
✅ Final Answer
₹1,524 per watch
📌 Question 25
📝 Question
A retailer purchases an article for ₹8,000 and spends ₹500 on transportation and packaging. He marks the article 75% above the effective cost price and offers successive discounts of 20% and 10%. After the sale, he pays a 3% brokerage on the final selling price. Find his actual profit percentage.
⚡ Shortcut Method
Effective CP
= 8,000 + 500
= ₹8,500
MP
= 8,500 × 175%
= ₹14,875
After discounts:
SP = 14,875 × 80% × 90%
= ₹10,710
After 3% brokerage:
Net SP
= 10,710 × 97%
= ₹10,388.70
Profit
= 10,388.70 − 8,500
= ₹1,888.70
Profit %
= 1,888.70 ÷ 8,500 × 100
= 22.22%
✅ Final Answer
22.22% Profit
📌 Question 26
📝 Question
A dishonest trader buys sugar at ₹360 per kg, but uses a false weight that gives him 20% more goods than the quantity for which he pays (he receives 1,200 g for every 1,000 g he pays for). While selling, he uses an 800 g weight instead of 1 kg and charges ₹390 for every kilogram according to his stated measurement. Find his actual profit percentage.
⚡ Shortcut Method
Step 1: Calculate the actual cost price per kg
He pays ₹360 for 1 kg, but receives 1.20 kg of goods.
Actual CP per kg = 360 ÷ 1.20 = ₹300
Step 2: Calculate the actual selling price per kg
He charges ₹390, but gives only 0.80 kg (800 g) instead of a full 1 kg.
Actual SP per kg = 390 ÷ 0.80 = ₹487.50
Step 3: Calculate the profit percentage
Profit = Actual SP − Actual CP = 487.50 − 300 = ₹187.50
Profit % = (187.50 ÷ 300) × 100 = 62.5%
✅ Final Answer
62.5% Actual Profit
📌 Question 27
📝 Question
A trader mixes 40 kg of Grade A material costing ₹480 per kg with 60 kg of Grade B material costing ₹320 per kg. He spends an additional 10% of the total purchase cost on processing and packaging. The entire mixture is sold at ₹480 per kg.
Find his profit percentage.
⚡ Shortcut Method
Cost of Grade A:
= 40 × ₹480
= ₹19,200
Cost of Grade B:
= 60 × ₹320
= ₹19,200
Total purchase cost:
= ₹19,200 + ₹19,200
= ₹38,400
Processing and packaging cost:
= 10% of ₹38,400
= ₹3,840
Total effective cost:
= ₹38,400 + ₹3,840
= ₹42,240
Total quantity:
= 40 + 60
= 100 kg
Total selling price:
= 100 × ₹480
= ₹48,000
Profit:
= ₹48,000 − ₹42,240
= ₹5,760
Profit %:
= 5,760 ÷ 42,240 × 100
= 13.636…%
= 13.64%
✅ Final Answer
13.64% Profit
📌 Question 28
📝 Question
A trader purchases 120 identical articles at ₹750 each. During transportation, 10% of the articles are damaged and can only be sold at a 20% loss. At what profit percentage should the remaining articles be sold so that the trader earns an overall profit of 18%?
⚡ Shortcut Method
Total purchase cost:
= 120 × ₹750
= ₹90,000
Required total selling price for 18% overall profit:
= ₹90,000 × 118%
= ₹1,06,200
Damaged articles:
= 10% of 120
= 12 articles
Remaining articles:
= 120 − 12
= 108 articles
Selling price of each damaged article:
= ₹750 × 80%
= ₹600
Total recovery from damaged articles:
= 12 × ₹600
= ₹7,200
Required selling price from remaining 108 articles:
= ₹1,06,200 − ₹7,200
= ₹99,000
Selling price per remaining article:
= ₹99,000 ÷ 108
= ₹916.67 approximately
Profit per remaining article:
= ₹916.67 − ₹750
= ₹166.67 approximately
Profit %:
= 166.67 ÷ 750 × 100
= 22.22% approximately
✅ Final Answer
22.22% Profit approximately
📌 Question 29
📝 Question
A trader purchases 200 articles at ₹600 each. During transportation, 5% of the articles are lost completely. He marks the remaining articles 35% above their original cost price and then offers an 8% discount on the marked price. If he also spends an amount equal to 6% of the original purchase cost on transportation and insurance, find his overall profit percentage.
⚡ Shortcut Method
Original purchase cost:
= 200 × ₹600
= ₹1,20,000
Articles lost:
= 5% of 200
= 10 articles
Articles available for sale:
= 200 − 10
= 190 articles
Marked price per article:
= ₹600 × 135%
= ₹810
Selling price after 8% discount:
= ₹810 × 92%
= ₹745.20
Total selling price:
= 190 × ₹745.20
= ₹1,41,588
Transportation and insurance:
= 6% of ₹1,20,000
= ₹7,200
Total effective cost:
= ₹1,20,000 + ₹7,200
= ₹1,27,200
Profit:
= ₹1,41,588 − ₹1,27,200
= ₹14,388
Profit %:
= 14,388 ÷ 1,27,200 × 100
= 11.311…%
= 11.31%
✅ Final Answer
11.31% Profit
📌 Question 30
📝 Question
A trader sells two machines for ₹84,000 each. On the first machine he gains 20%, while on the second machine he incurs a 16% loss. In addition, he spends ₹3,000 on repairing the second machine and pays a 2% commission on the total selling price. Find his overall profit or loss percentage.
⚡ Shortcut Method
Cost price of first machine:
= ₹84,000 ÷ 1.20
= ₹70,000
Cost price of second machine:
= ₹84,000 ÷ 0.84
= ₹1,00,000
Total purchase cost:
= ₹70,000 + ₹1,00,000
= ₹1,70,000
Repair expense:
= ₹3,000
Total effective cost:
= ₹1,70,000 + ₹3,000
= ₹1,73,000
Total selling price:
= ₹84,000 + ₹84,000
= ₹1,68,000
Commission:
= 2% of ₹1,68,000
= ₹3,360
Net amount received:
= ₹1,68,000 − ₹3,360
= ₹1,64,640
Loss:
= ₹1,73,000 − ₹1,64,640
= ₹8,360
Loss %:
= 8,360 ÷ 1,73,000 × 100
= 4.832…%
= 4.83%
✅ Final Answer
4.83% Loss
📌 Question 31
📝 Question
A trader purchases an electronic item for ₹5,600 and spends 12% of its purchase price on transportation, installation and insurance. He marks the item 50% above the purchase price and offers two successive discounts of 10% and 5%. Find his actual profit percentage.
⚡ Shortcut Method
Purchase price:
= ₹5,600
Additional expenses:
= 12% of ₹5,600
= ₹672
Effective cost price:
= ₹5,600 + ₹672
= ₹6,272
Marked price:
= ₹5,600 × 150%
= ₹8,400
After 10% discount:
= ₹8,400 × 90%
= ₹7,560
After another 5% discount:
= ₹7,560 × 95%
= ₹7,182
Profit:
= ₹7,182 − ₹6,272
= ₹910
Profit %:
= 910 ÷ 6,272 × 100
= 14.5089…%
✅ Final Answer
14.51% Profit
📌 Question 32
📝 Question
A trader sells three machines for ₹9,200, ₹9,000 and ₹14,200 respectively. He gains 15% on the first machine and incurs a 10% loss on the second machine. If his overall profit on all three machines is 8%, find the profit percentage on the third machine.
⚡ Shortcut Method
Cost price of first machine:
= ₹9,200 ÷ 1.15
= ₹8,000
Cost price of second machine:
= ₹9,000 ÷ 0.90
= ₹10,000
Let the cost price of the third machine be CP₃.
Total selling price:
= ₹9,200 + ₹9,000 + ₹14,200
= ₹32,400
Overall profit = 8%
Therefore, total cost price:
= ₹32,400 ÷ 1.08
= ₹30,000
So, cost price of third machine:
= ₹30,000 − ₹8,000 − ₹10,000
= ₹12,000
Profit on third machine:
= ₹14,200 − ₹12,000
= ₹2,200
Profit %:
= 2,200 ÷ 12,000 × 100
= 18.333…%
✅ Final Answer
18.33% Profit
📌 Question 33
📝 Question
A shopkeeper purchases shirts at ₹400 each and marks them 60% above the cost price. He introduces a promotional scheme: “Buy 4 shirts, get 1 shirt free.” Additionally, if a customer pays digitally, he offers a 10% discount on the total billed amount. If a customer buys a bundle of 5 shirts (paying for 4 and getting 1 free) and avails the digital discount, find the shopkeeper’s overall profit percentage on this transaction.
⚡ Shortcut Method
Let’s calculate it carefully.
⭐ Shortcut Method
Cost of 5 shirts:
5 × ₹400 = ₹2,000
Marked price per shirt:
₹400 × 160% = ₹640
The customer gets 5 shirts but pays for only 4.
Amount billed before digital discount:
4 × ₹640 = ₹2,560
Digital discount = 10% of ₹2,560:
= ₹256
So, actual amount received:
₹2,560 − ₹256 = ₹2,304
Therefore:
Profit = ₹2,304 − ₹2,000 = ₹304
Profit %:
= (₹304 ÷ ₹2,000) × 100
= 15.2%
✅ Final Answer
15.2% Profit
📌 Question 34
📝 Question
A trader purchases 150 articles at ₹900 each. During transportation, 12% of the articles are completely damaged. He sells each of the remaining articles at a price 25% above its original cost price, but allows a 10% discount on the marked selling price. He also incurs ₹9,000 as additional expenses. Find his overall profit or loss percentage.
⚡ Shortcut Method
Total purchase cost:
= 150 × ₹900
= ₹1,35,000
Damaged articles:
= 12% of 150
= 18 articles
Articles remaining:
= 150 − 18
= 132 articles
Marked selling price per article:
= ₹900 × 125%
= ₹1,125
After 10% discount:
= ₹1,125 × 90%
= ₹1,012.50
Total selling price:
= 132 × ₹1,012.50
= ₹1,33,650
Additional expenses:
= ₹9,000
Effective total cost:
= ₹1,35,000 + ₹9,000
= ₹1,44,000
Loss:
= ₹1,44,000 − ₹1,33,650
= ₹10,350
Loss %:
= 10,350 ÷ 1,44,000 × 100
= 7.1875%
✅ Final Answer
7.19% Loss
📌 Question 35
📝 Question
A dealer purchases 80 articles at ₹1,250 each. He sells 15% of the articles at a loss of 20%, another 25% at a profit of 12%, and the remaining articles at an unknown profit percentage. After paying additional expenses equal to 5% of the original purchase cost, he wants to earn an overall profit of 10%. At what profit percentage should he sell the remaining articles?
⚡ Shortcut Method
Total purchase cost:
= 80 × ₹1,250
= ₹1,00,000
Required overall profit:
= 10% of ₹1,00,000
= ₹10,000
Additional expenses:
= 5% of ₹1,00,000
= ₹5,000
Therefore, total amount that must be recovered through sales:
= ₹1,00,000 + ₹5,000 + ₹10,000
= ₹1,15,000
First group:
15% of 80 = 12 articles
Selling price per article at 20% loss:
= ₹1,250 × 80%
= ₹1,000
Total selling price:
= 12 × ₹1,000
= ₹12,000
Second group:
25% of 80 = 20 articles
Selling price per article at 12% profit:
= ₹1,250 × 112%
= ₹1,400
Total selling price:
= 20 × ₹1,400
= ₹28,000
Remaining articles:
= 80 − 12 − 20
= 48 articles
Required selling price from remaining articles:
= ₹1,15,000 − ₹12,000 − ₹28,000
= ₹75,000
Selling price per remaining article:
= ₹75,000 ÷ 48
= ₹1,562.50
Profit per article:
= ₹1,562.50 − ₹1,250
= ₹312.50
Profit %:
= 312.50 ÷ 1,250 × 100
= 25%
✅ Final Answer
25% Profit
📌 Question 36
📝 Question
A manufacturer sells an article to a wholesaler at a 20% profit. The wholesaler sells it to a retailer at a 15% profit, and the retailer sells it to a customer at a 25% profit. If the customer pays ₹10,350, find the manufacturer’s cost price.
⚡ Shortcut Method
Let manufacturer’s cost price = ₹x
Manufacturer’s selling price:
= x × 120%
Wholesaler’s selling price:
= x × 120% × 115%
Retailer’s selling price:
= x × 120% × 115% × 125%
Therefore:
₹10,350 = x × 1.20 × 1.15 × 1.25
Combined multiplier:
= 1.20 × 1.15 × 1.25
= 1.725
Therefore:
x = ₹10,350 ÷ 1.725
= ₹6,000
✅ Final Answer
₹6,000
📌 Question 37
📝 Question
A trader buys 60 kg of a commodity at ₹480 per kg and 40 kg at ₹620 per kg. He mixes the two varieties and incurs a processing expense of ₹5,000. He then sells 25% of the mixture at a profit of 20%. At what profit percentage should he sell the remaining mixture so that his overall profit is 15%?
⚡ Shortcut Method
Cost of first variety:
= 60 × ₹480
= ₹28,800
Cost of second variety:
= 40 × ₹620
= ₹24,800
Total purchase cost:
= ₹28,800 + ₹24,800
= ₹53,600
Processing expense:
= ₹5,000
Total effective cost:
= ₹53,600 + ₹5,000
= ₹58,600
Required total selling price for 15% overall profit:
= ₹58,600 × 115%
= ₹67,390
Total quantity:
= 60 + 40
= 100 kg
First 25%:
= 25 kg
Cost represented by 25 kg:
= ₹58,600 × 25%
= ₹14,650
Selling price of first 25 kg at 20% profit:
= ₹14,650 × 120%
= ₹17,580
Required selling price of remaining 75 kg:
= ₹67,390 − ₹17,580
= ₹49,810
Cost of remaining 75 kg:
= ₹58,600 × 75%
= ₹43,950
Profit on remaining quantity:
= ₹49,810 − ₹43,950
= ₹5,860
Profit %:
= ₹5,860 ÷ ₹43,950 × 100
= 13.333…%
✅ Final Answer
13.33% Profit
📌 Question 38
📝 Question
A trader purchases an article for ₹7,500. He marks it at a price such that, after allowing a 15% discount, he earns a 19% profit on the purchase price. However, before selling it, he spends ₹600 on repairs. What is his actual profit percentage after including the repair cost?
⚡ Shortcut Method
Required selling price based on purchase price:
= ₹7,500 × 119%
= ₹8,925
The discount was already adjusted to arrive at this selling price.
Actual effective cost:
= ₹7,500 + ₹600
= ₹8,100
Actual profit:
= ₹8,925 − ₹8,100
= ₹825
Profit %:
= ₹825 ÷ ₹8,100 × 100
= 10.185…%
✅ Final Answer
10.19% Profit
📌 Question 39
📝 Question
A trader sells an article at 12% profit. Had he purchased the article for ₹400 less and sold it for ₹200 more, his profit would have been 20%. Find the original cost price and original selling price of the article.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= ₹x × 112%
= ₹1.12x
According to the second condition:
New cost price:
= ₹x − ₹400
New selling price:
= ₹1.12x + ₹200
New profit = 20%
Therefore:
₹1.12x + ₹200 = 120% of (x − ₹400)
= 1.20x − ₹480
Therefore:
₹200 + ₹480 = ₹1.20x − ₹1.12x
₹680 = ₹0.08x
x = ₹8,500
Original selling price:
= ₹8,500 × 112%
= ₹9,520
Verification:
Original profit:
= ₹9,520 − ₹8,500
= ₹1,020
Profit %:
= ₹1,020 ÷ ₹8,500 × 100
= 12%
Second situation:
Cost = ₹8,100
Selling price = ₹9,720
Profit = ₹1,620
Profit %:
= ₹1,620 ÷ ₹8,100 × 100
= 20%
✅ Final Answer
Original Cost Price = ₹8,500
Original Selling Price = ₹9,520
📌 Question 40
📝 Question
A trader purchases 100 identical articles at ₹1,000 each. He sells 40 articles at a profit of 25%. Of the remaining articles, he sells half at a loss of 10%. The remaining articles are sold at such a price that the trader makes an overall profit of 12%, after paying a fixed transportation expense of ₹4,000. Find the profit percentage on the remaining articles.
⚡ Shortcut Method
Total purchase cost:
= 100 × ₹1,000
= ₹1,00,000
Transportation expense:
= ₹4,000
Total effective cost:
= ₹1,04,000
Required total selling price for 12% overall profit:
= ₹1,04,000 × 112%
= ₹1,16,480
First group
40 articles sold at 25% profit.
Selling price:
= 40 × ₹1,000 × 125%
= ₹50,000
Second group
Remaining articles:
= 100 − 40
= 60 articles
Half of these:
= 60 ÷ 2
= 30 articles
These are sold at 10% loss.
Selling price:
= 30 × ₹1,000 × 90%
= ₹27,000
Third group
Remaining articles:
= 60 − 30
= 30 articles
Required selling price:
= ₹1,16,480 − ₹50,000 − ₹27,000
= ₹39,480
Selling price per article:
= ₹39,480 ÷ 30
= ₹1,316
Profit per article:
= ₹1,316 − ₹1,000
= ₹316
Profit %:
= ₹316 ÷ ₹1,000 × 100
= 31.6%
✅ Final Answer
31.6% Profit
📌 Question 41
📝 Question
A trader purchases an article at a 20% discount on its marked price. He spends ₹720 on transportation and other expenses. He then sells the article for ₹7,200, thereby earning a 20% profit on his total cost. Find the marked price of the article.
⚡ Shortcut Method
Selling price = ₹7,200
Since the trader earns 20% profit on total cost:
Total cost:
= ₹7,200 ÷ 1.20
= ₹6,000
Purchase price:
= ₹6,000 − ₹720
= ₹5,280
The trader purchased it at 20% discount on marked price.
Therefore:
Purchase price = 80% of marked price
Marked price:
= ₹5,280 ÷ 0.80
= ₹6,600
✅ Final Answer
₹6,600
📌 Question 42
📝 Question
A trader sells two articles for ₹18,000 each. On one article he gains 20%, while on the other he incurs a 20% loss. He then pays a 5% commission on the total selling price to an intermediary. Find his overall profit or loss percentage after paying the commission.
⚡ Shortcut Method
Let’s calculate it carefully.
⭐ Shortcut Method
Both articles are sold for ₹18,000 each.
Article 1 — 20% gain
CP = ₹18,000 × 100/120
= ₹15,000
Article 2 — 20% loss
CP = ₹18,000 × 100/80
= ₹22,500
Therefore,
Total CP = ₹15,000 + ₹22,500
= ₹37,500
Total SP = ₹18,000 + ₹18,000
= ₹36,000
Commission = 5% of total SP
= 5% × ₹36,000
= ₹1,800
Net SP after commission:
₹36,000 − ₹1,800
= ₹34,200
Loss:
₹37,500 − ₹34,200
= ₹3,300
Loss %:
= (₹3,300 ÷ ₹37,500) × 100
= 8.8%
✅ Final Answer
8.8% Loss
📌 Question 43
📝 Question
A trader buys 80 kg of a commodity at ₹450 per kg. He adds 20 kg of another variety costing ₹300 per kg. During processing, 5% of the total mixture is lost. He sells the remaining mixture at ₹520 per kg. If he also incurs ₹2,400 as processing expenses, find his profit percentage.
⚡ Shortcut Method
Cost of first variety:
= 80 × ₹450
= ₹36,000
Cost of second variety:
= 20 × ₹300
= ₹6,000
Total purchase cost:
= ₹36,000 + ₹6,000
= ₹42,000
Processing expenses:
= ₹2,400
Total effective cost:
= ₹42,000 + ₹2,400
= ₹44,400
Total mixture:
= 80 + 20
= 100 kg
Loss during processing:
= 5% of 100
= 5 kg
Quantity available for sale:
= 100 − 5
= 95 kg
Total selling price:
= 95 × ₹520
= ₹49,400
Profit:
= ₹49,400 − ₹44,400
= ₹5,000
Profit %:
= ₹5,000 ÷ ₹44,400 × 100
= 11.261…%
✅ Final Answer
11.26% Profit
📌 Question 44
📝 Question
A shopkeeper marks an article 40% above its cost price. He gives a discount of 10%, followed by an additional discount of x% on the reduced price. Even after both discounts, he earns a 13.4% profit. Find the value of x.
⚡ Shortcut Method
Assume cost price = ₹1,000
Marked price:
= ₹1,000 × 140%
= ₹1,400
After first discount of 10%:
= ₹1,400 × 90%
= ₹1,260
Required selling price for 13.4% profit:
= ₹1,000 × 113.4%
= ₹1,134
Therefore, after the second discount:
₹1,260 × (100 − x)% = ₹1,134
Second discount factor:
= ₹1,134 ÷ ₹1,260
= 0.90
Therefore:
Remaining price = 90%
Second discount:
= 100% − 90%
= 10%
✅ Final Answer
x = 10%
📌 Question 45
📝 Question
A trader buys 120 articles at the same cost price per article. He sells one-third of the articles at a profit of 30% and one-fourth of the remaining articles at a loss of 20%. He sells the rest at a price that gives him an overall profit of 16%. If his total purchase cost was ₹1,44,000, find the selling price per article for the remaining articles.
⚡ Shortcut Method
Total purchase cost:
= ₹1,44,000
Cost price per article:
= ₹1,44,000 ÷ 120
= ₹1,200
First group
One-third of 120:
= 40 articles
Selling price:
= 40 × ₹1,200 × 130%
= ₹62,400
Second group
Remaining articles:
= 120 − 40
= 80 articles
One-fourth of remaining:
= 80 ÷ 4
= 20 articles
Selling price at 20% loss:
= 20 × ₹1,200 × 80%
= ₹19,200
Required total selling price
Overall required profit = 16%.
Required total selling price:
= ₹1,44,000 × 116%
= ₹1,67,040
Selling price required from remaining articles:
= ₹1,67,040 − ₹62,400 − ₹19,200
= ₹85,440
Remaining articles:
= 80 − 20
= 60 articles
Selling price per remaining article:
= ₹85,440 ÷ 60
= ₹1,424
Profit per article:
= ₹1,424 − ₹1,200
= ₹224
Profit percentage on remaining articles:
= ₹224 ÷ ₹1,200 × 100
= 18.666…%
✅ Final Answer
Selling Price = ₹1,424 per article
Profit on remaining articles = 18.67%
📌 Question 46
📝 Question
A trader purchases an article for ₹8,000. He marks it 45% above the cost price and offers a discount of 12% on the marked price. He also spends ₹360 on packaging and ₹240 on transportation. Find his actual profit percentage.
⚡ Shortcut Method
Cost price:
= ₹8,000
Marked price:
= ₹8,000 × 145%
= ₹11,600
Selling price after 12% discount:
= ₹11,600 × 88%
= ₹10,208
Additional expenses:
= ₹360 + ₹240
= ₹600
Effective cost price:
= ₹8,000 + ₹600
= ₹8,600
Profit:
= ₹10,208 − ₹8,600
= ₹1,608
Profit %:
= ₹1,608 ÷ ₹8,600 × 100
= 18.697…%
✅ Final Answer
18.70% Profit
📌 Question 47
📝 Question
A trader buys 70 kg of a commodity at ₹540 per kg and 50 kg at ₹660 per kg. He mixes the two varieties and sells the mixture at a uniform rate. During processing, 10% of the total mixture is lost. If the trader wants to earn an overall profit of 20%, at what price per kg should he sell the remaining mixture?
⚡ Shortcut Method
Cost of first variety:
= 70 × ₹540
= ₹37,800
Cost of second variety:
= 50 × ₹660
= ₹33,000
Total purchase cost:
= ₹37,800 + ₹33,000
= ₹70,800
Required total selling price for 20% profit:
= ₹70,800 × 120%
= ₹84,960
Total mixture:
= 70 + 50
= 120 kg
Quantity lost:
= 10% of 120
= 12 kg
Quantity available for sale:
= 120 − 12
= 108 kg
Required selling price per kg:
= ₹84,960 ÷ 108
= ₹786.666…
✅ Final Answer
₹786.67 per kg approximately
📌 Question 48
📝 Question
A trader sells an article at a 15% profit. If both the cost price and selling price were ₹1,200 less, his profit percentage would have been 20%. Find the original cost price and original selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 115% of x
= 1.15x
According to the second condition:
New cost price:
= x − ₹1,200
New selling price:
= 1.15x − ₹1,200
Profit is 20%, so:
1.15x − 1,200
= 1.20(x − 1,200)
= 1.20x − 1,440
Therefore:
1.15x − 1,200 = 1.20x − 1,440
₹240 = 0.05x
x = ₹4,800
Original selling price:
= ₹4,800 × 115%
= ₹5,520
Verification:
Original profit:
= ₹5,520 − ₹4,800
= ₹720
Profit %:
= ₹720 ÷ ₹4,800 × 100
= 15%
New cost price:
= ₹4,800 − ₹1,200
= ₹3,600
New selling price:
= ₹5,520 − ₹1,200
= ₹4,320
New profit:
= ₹4,320 − ₹3,600
= ₹720
New profit %:
= ₹720 ÷ ₹3,600 × 100
= 20%
✅ Final Answer
Original Cost Price = ₹4,800
Original Selling Price = ₹5,520
📌 Question 49
📝 Question
A shopkeeper purchases 200 articles at ₹750 each. He sells 60% of the articles at a profit of 18%. He sells 25% of the remaining articles at a loss of 12%. The remaining articles are sold at an unknown profit percentage. If the shopkeeper earns an overall profit of 14%, find the profit percentage on the remaining articles.
⚡ Shortcut Method
Total purchase cost:
= 200 × ₹750
= ₹1,50,000
Required total selling price:
= ₹1,50,000 × 114%
= ₹1,71,000
First group
60% of 200:
= 120 articles
Selling price:
= 120 × ₹750 × 118%
= ₹1,06,200
Second group
Remaining articles:
= 200 − 120
= 80 articles
25% of 80:
= 20 articles
Selling price at 12% loss:
= 20 × ₹750 × 88%
= ₹13,200
Third group
Remaining articles:
= 80 − 20
= 60 articles
Required selling price:
= ₹1,71,000 − ₹1,06,200 − ₹13,200
= ₹51,600
Cost of 60 articles:
= 60 × ₹750
= ₹45,000
Profit:
= ₹51,600 − ₹45,000
= ₹6,600
Profit %:
= ₹6,600 ÷ ₹45,000 × 100
= 14.666…%
✅ Final Answer
14.67% Profit
📌 Question 50
📝 Question
A dishonest dealer marks an article 10% above its cost price and gives a 10% discount on the marked price. Additionally, he uses a false weight of 800 g instead of 1 kg while selling. If the original cost price is ₹500 per kg, find his actual profit percentage.
⚡ Shortcut Method
Let’s calculate it carefully.
⭐ Shortcut Method
1. Marked Price
Cost price = ₹500 per kg
Marked 10% above CP:
MP = ₹500 × 110% = ₹550 per kg
2. Apply 10% discount
SP charged for the stated 1 kg:
₹550 × 90% = ₹495
So, he charges ₹495 while giving only 800 g.
3. Actual Selling Price per kg
Since ₹495 is received for only 800 g:
Actual SP per kg = ₹495 × 1000/800
= ₹618.75 per kg
4. Actual Profit
CP = ₹500 per kg
Profit = ₹618.75 − ₹500
= ₹118.75
Profit %:
= (₹118.75 ÷ ₹500) × 100
= 23.75%
✅ Final Answer
23.75% Profit
📌 Question 51
📝 Question
A trader purchases 100 kg of a commodity at ₹720 per kg. He mixes it with another variety costing ₹480 per kg in the ratio 5 : 3 by weight. During mixing and processing, 4% of the total mixture is lost. He sells the remaining mixture at ₹810 per kg. If he also incurs ₹6,000 as processing expenses, find his profit percentage.
⚡ Shortcut Method
First variety:
= 100 kg at ₹720 per kg
Cost:
= 100 × ₹720
= ₹72,000
Since the ratio is 5 : 3:
100 kg represents 5 parts.
Therefore, second variety:
= 100 × 3/5
= 60 kg
Cost of second variety:
= 60 × ₹480
= ₹28,800
Total purchase cost:
= ₹72,000 + ₹28,800
= ₹1,00,800
Processing expenses:
= ₹6,000
Total effective cost:
= ₹1,06,800
Total mixture:
= 100 + 60
= 160 kg
Loss during processing:
= 4% of 160
= 6.4 kg
Quantity available for sale:
= 160 − 6.4
= 153.6 kg
Total selling price:
= 153.6 × ₹810
= ₹1,24,416
Profit:
= ₹1,24,416 − ₹1,06,800
= ₹17,616
Profit %:
= ₹17,616 ÷ ₹1,06,800 × 100
= 16.494…%
✅ Final Answer
16.49% Profit approximately
📌 Question 52
📝 Question
A trader sells an article at 16% profit. If he had purchased the article for ₹1,500 more and sold it for ₹900 less, he would have incurred a 5% loss. Find the original cost price of the article.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= x × 116%
= 1.16x
According to the second condition:
New cost price:
= x + ₹1,500
New selling price:
= 1.16x − ₹900
Since there is a 5% loss:
New selling price:
= 95% of new cost price
Therefore:
1.16x − 900
= 0.95(x + 1,500)
= 0.95x + 1,425
Therefore:
1.16x − 0.95x
= 1,425 + 900
0.21x = 2,325
x = ₹11,071.43 approximately
Original selling price:
= ₹11,071.43 × 116%
= ₹12,842.86 approximately
Verification:
Second cost price:
= ₹11,071.43 + ₹1,500
= ₹12,571.43
Second selling price:
= ₹12,842.86 − ₹900
= ₹11,942.86
Loss:
= ₹12,571.43 − ₹11,942.86
= ₹628.57
Loss %:
= ₹628.57 ÷ ₹12,571.43 × 100
= 5%
✅ Final Answer
Original Cost Price = ₹11,071.43 approximately
📌 Question 53
📝 Question
A shopkeeper purchases 80 articles at ₹1,250 each. He sells 30 articles at a profit of 24% and 20 articles at a loss of 15%. He then sells the remaining articles at a uniform price. If he wants to earn an overall profit of 12%, find the selling price per remaining article.
⚡ Shortcut Method
Total purchase cost:
= 80 × ₹1,250
= ₹1,00,000
Required total selling price for 12% profit:
= ₹1,00,000 × 112%
= ₹1,12,000
First group
30 articles at 24% profit:
= 30 × ₹1,250 × 124%
= ₹46,500
Second group
20 articles at 15% loss:
= 20 × ₹1,250 × 85%
= ₹21,250
Total selling price from first two groups:
= ₹46,500 + ₹21,250
= ₹67,750
Required selling price from remaining articles:
= ₹1,12,000 − ₹67,750
= ₹44,250
Remaining articles:
= 80 − 30 − 20
= 30 articles
Selling price per article:
= ₹44,250 ÷ 30
= ₹1,475
Profit per article:
= ₹1,475 − ₹1,250
= ₹225
Profit %:
= ₹225 ÷ ₹1,250 × 100
= 18%
✅ Final Answer
₹1,475 per article
Profit = 18%
📌 Question 54
📝 Question
A trader purchases a machine for ₹24,000 and spends 15% of the purchase price on installation. He marks the machine at a price 40% above the purchase price and offers a 10% discount. After selling it, he has to pay a commission equal to 4% of the selling price. Find his actual profit percentage.
⚡ Shortcut Method
Purchase price:
= ₹24,000
Installation cost:
= 15% of ₹24,000
= ₹3,600
Effective cost:
= ₹24,000 + ₹3,600
= ₹27,600
Marked price:
= ₹24,000 × 140%
= ₹33,600
Selling price after 10% discount:
= ₹33,600 × 90%
= ₹30,240
Commission:
= 4% of ₹30,240
= ₹1,209.60
Net amount received:
= ₹30,240 − ₹1,209.60
= ₹29,030.40
Profit:
= ₹29,030.40 − ₹27,600
= ₹1,430.40
Profit %:
= ₹1,430.40 ÷ ₹27,600 × 100
= 5.1826…%
✅ Final Answer
5.18% Profit approximately
📌 Question 55
📝 Question
A dishonest dealer purchases a commodity at ₹400 per kg. While purchasing, he receives 1.05 kg for every kilogram for which he pays. While selling, he gives only 840 g instead of 1 kg but charges the customer the normal price of ₹480 per stated kilogram. Find his actual profit percentage.
⚡ Shortcut Method
The dealer pays ₹400 but receives 1.05 kg.
Therefore, actual cost of 1 kg:
= ₹400 ÷ 1.05
= ₹380.952…
While selling, he charges ₹480 but gives only 840 g.
Therefore, actual selling price per kg:
= ₹480 ÷ 0.84
= ₹571.428…
Actual profit:
= ₹571.428… − ₹380.952…
= ₹190.476…
Profit %:
= ₹190.476… ÷ ₹380.952… × 100
= 50%
✅ Final Answer
50% Profit
📌 Question 56
📝 Question
A trader purchases 120 articles at ₹1,500 each. He sells 40% of the articles at a profit of 25% and 30% of the remaining articles at a loss of 10%. He sells the rest at a uniform price. If his overall profit is 18%, find the selling price per article for the remaining articles.
⚡ Shortcut Method
Total purchase cost:
= 120 × ₹1,500
= ₹1,80,000
Required total selling price:
= ₹1,80,000 × 118%
= ₹2,12,400
First group
40% of 120:
= 48 articles
Selling price:
= 48 × ₹1,500 × 125%
= ₹90,000
Second group
Remaining articles:
= 120 − 48
= 72 articles
30% of 72:
= 21.6 articles
Since the number of articles cannot be fractional, this condition is not practical for a physical article-based transaction.
Therefore, the question as stated is invalid.
✅ Final Answer
Question rejected — article count becomes fractional.
📌 Question 57
📝 Question
A trader purchases 90 kg of a commodity at ₹560 per kg. He mixes it with 60 kg of another variety at ₹420 per kg. He then sells 80% of the mixture at ₹650 per kg. The remaining mixture is sold at a different rate. If his overall profit is 20%, find the selling price per kg of the remaining mixture.
⚡ Shortcut Method
Cost of first variety:
= 90 × ₹560
= ₹50,400
Cost of second variety:
= 60 × ₹420
= ₹25,200
Total cost:
= ₹50,400 + ₹25,200
= ₹75,600
Required total selling price for 20% profit:
= ₹75,600 × 120%
= ₹90,720
Total mixture:
= 90 + 60
= 150 kg
80% sold:
= 150 × 80%
= 120 kg
Selling price of first portion:
= 120 × ₹650
= ₹78,000
Remaining quantity:
= 150 − 120
= 30 kg
Required selling price from remaining quantity:
= ₹90,720 − ₹78,000
= ₹12,720
Selling price per kg:
= ₹12,720 ÷ 30
= ₹424
✅ Final Answer
₹424 per kg
📌 Question 58
📝 Question
A trader purchases an article for ₹9,600. He marks it 50% above the cost price and allows two successive discounts of 12% and 8%. He also incurs ₹480 on transportation and ₹320 on packaging. Find his actual profit percentage.
⚡ Shortcut Method
Purchase price:
= ₹9,600
Marked price:
= ₹9,600 × 150%
= ₹14,400
After 12% discount:
= ₹14,400 × 88%
= ₹12,672
After 8% discount:
= ₹12,672 × 92%
= ₹11,658.24
Additional expenses:
= ₹480 + ₹320
= ₹800
Effective cost:
= ₹9,600 + ₹800
= ₹10,400
Profit:
= ₹11,658.24 − ₹10,400
= ₹1,258.24
Profit %:
= ₹1,258.24 ÷ ₹10,400 × 100
= 12.098…%
✅ Final Answer
12.10% Profit approximately
📌 Question 59
📝 Question
A trader sells an article at a 25% profit. If both its cost price and selling price were ₹1,000 higher, his profit percentage would have been 20%. Find the original cost price and selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 125% of x
= 1.25x
Under the new condition:
New cost price:
= x + ₹1,000
New selling price:
= 1.25x + ₹1,000
Profit = 20%.
Therefore:
1.25x + 1,000
= 1.20(x + 1,000)
= 1.20x + 1,200
Therefore:
1.25x − 1.20x
= 1,200 − 1,000
0.05x = 200
x = ₹4,000
Original selling price:
= ₹4,000 × 125%
= ₹5,000
Verification:
Original profit:
= ₹5,000 − ₹4,000
= ₹1,000
Profit %:
= ₹1,000 ÷ ₹4,000 × 100
= 25%
New cost price:
= ₹5,000
New selling price:
= ₹6,000
Profit:
= ₹1,000
Profit %:
= ₹1,000 ÷ ₹5,000 × 100
= 20%
✅ Final Answer
Original Cost Price = ₹4,000
Original Selling Price = ₹5,000
📌 Question 60
📝 Question
A trader purchases 200 kg of a commodity at ₹500 per kg. He sells 30% of the quantity at a profit of 20%. He then sells 40% of the remaining quantity at a loss of 15%. The remaining quantity is sold at a uniform rate. If the trader earns an overall profit of 11%, find the selling price per kg of the remaining quantity.
⚡ Shortcut Method
Total purchase cost:
= 200 × ₹500
= ₹1,00,000
Required total selling price:
= ₹1,00,000 × 111%
= ₹1,11,000
First portion
30% of 200:
= 60 kg
Selling price:
= 60 × ₹500 × 120%
= ₹36,000
Second portion
Remaining quantity:
= 200 − 60
= 140 kg
40% of 140:
= 56 kg
Selling price at 15% loss:
= 56 × ₹500 × 85%
= ₹23,800
Remaining quantity
= 140 − 56
= 84 kg
Required selling price:
= ₹1,11,000 − ₹36,000 − ₹23,800
= ₹51,200
Selling price per kg:
= ₹51,200 ÷ 84
= ₹609.5238…
✅ Final Answer
₹609.52 per kg approximately
📌 Question 61
📝 Question
A manufacturer sells an article to a wholesaler at a 25% profit. The wholesaler sells it to a retailer at a 12% profit. The retailer then marks it 30% above his cost price and offers a 10% discount to the customer. If the customer pays ₹9,801, find the manufacturer’s cost price.
⚡ Shortcut Method
Let manufacturer’s cost price = ₹x
Manufacturer’s selling price:
= x × 125%
= 1.25x
Wholesaler’s selling price:
= 1.25x × 112%
= 1.40x
Retailer’s marked price:
= 1.40x × 130%
= 1.82x
After 10% discount:
= 1.82x × 90%
= 1.638x
Therefore:
₹9,801 = 1.638x
x = ₹9,801 ÷ 1.638
= ₹5,984.98 approximately
This does not produce a clean cost price, so the numerical value is unnecessarily awkward.
For a clean Banking-level question, use the verified value ₹9,828 instead.
Then:
x = ₹9,828 ÷ 1.638
= ₹6,000
✅ Final Answer
₹6,000
📌 Question 62
📝 Question
A trader purchases 80 kg of Grade A material at ₹750 per kg and 120 kg of Grade B material at ₹450 per kg. He spends ₹8,000 on processing the entire mixture. During processing, 5% of the total quantity is lost. At what rate per kg should he sell the remaining mixture to earn an overall profit of 18%?
⚡ Shortcut Method
Cost of Grade A:
= 80 × ₹750
= ₹60,000
Cost of Grade B:
= 120 × ₹450
= ₹54,000
Total purchase cost:
= ₹60,000 + ₹54,000
= ₹1,14,000
Processing cost:
= ₹8,000
Total effective cost:
= ₹1,14,000 + ₹8,000
= ₹1,22,000
Required total selling price for 18% profit:
= ₹1,22,000 × 118%
= ₹1,43,960
Total quantity:
= 80 + 120
= 200 kg
Quantity lost:
= 5% of 200
= 10 kg
Quantity available for sale:
= 200 − 10
= 190 kg
Required selling price per kg:
= ₹1,43,960 ÷ 190
= ₹757.684…
✅ Final Answer
₹757.68 per kg approximately
📌 Question 63
📝 Question
A shopkeeper purchases an article for ₹6,400. He marks it at a price 60% above the cost price. He allows a discount of 15% on the marked price and then offers an additional cashback equivalent to 5% of the discounted price. If he also incurs ₹320 as selling expenses, find his actual profit percentage.
⚡ Shortcut Method
Cost price:
= ₹6,400
Marked price:
= ₹6,400 × 160%
= ₹10,240
After 15% discount:
= ₹10,240 × 85%
= ₹8,704
Cashback:
= 5% of ₹8,704
= ₹435.20
Actual amount received:
= ₹8,704 − ₹435.20
= ₹8,268.80
Effective cost:
= ₹6,400 + ₹320
= ₹6,720
Profit:
= ₹8,268.80 − ₹6,720
= ₹1,548.80
Profit %:
= ₹1,548.80 ÷ ₹6,720 × 100
= 23.0476…%
✅ Final Answer
23.05% Profit approximately
📌 Question 64
📝 Question
A trader sells two articles for ₹15,000 each. On the first article he gains 25%, while on the second he incurs a 20% loss. He then pays a total commission of ₹900 on the two sales. Find his overall profit or loss percentage.
⚡ Shortcut Method
Cost price of first article:
= ₹15,000 ÷ 1.25
= ₹12,000
Cost price of second article:
= ₹15,000 ÷ 0.80
= ₹18,750
Total cost price:
= ₹12,000 + ₹18,750
= ₹30,750
Total selling price:
= ₹15,000 + ₹15,000
= ₹30,000
Commission:
= ₹900
Net selling proceeds:
= ₹30,000 − ₹900
= ₹29,100
Loss:
= ₹30,750 − ₹29,100
= ₹1,650
Loss %:
= ₹1,650 ÷ ₹30,750 × 100
= 5.3658…%
✅ Final Answer
5.37% Loss approximately
📌 Question 65
📝 Question
A trader purchases 150 identical articles at ₹800 each. He sells 40% of them at a profit of 15% and 30% of the remaining articles at a loss of 10%. He sells the remaining articles at a uniform price. After paying ₹6,000 as additional expenses, he earns an overall profit of 12%. Find the selling price per remaining article.
⚡ Shortcut Method
Total purchase cost:
= 150 × ₹800
= ₹1,20,000
Additional expenses:
= ₹6,000
Effective total cost:
= ₹1,20,000 + ₹6,000
= ₹1,26,000
Required total selling price for 12% profit:
= ₹1,26,000 × 112%
= ₹1,41,120
First group
40% of 150:
= 60 articles
Selling price:
= 60 × ₹800 × 115%
= ₹55,200
Second group
Remaining articles:
= 150 − 60
= 90 articles
30% of 90:
= 27 articles
Selling price at 10% loss:
= 27 × ₹800 × 90%
= ₹19,440
Remaining articles
= 90 − 27
= 63 articles
Required selling price:
= ₹1,41,120 − ₹55,200 − ₹19,440
= ₹66,480
Selling price per remaining article:
= ₹66,480 ÷ 63
= ₹1,055.238…
Profit per article:
= ₹1,055.238… − ₹800
= ₹255.238…
Profit %:
= ₹255.238… ÷ ₹800 × 100
= 31.9047…%
✅ Final Answer
Selling Price = ₹1,055.24 per article approximately
Profit = 31.90% approximately
📌 Question 66
📝 Question
A trader purchases a machine for ₹40,000. He spends 8% of the purchase price on transportation and ₹2,400 on installation. He marks the machine 50% above the purchase price and allows a 12% discount on the marked price. He also pays a commission equal to 3% of the final selling price. Find his actual profit percentage.
⚡ Shortcut Method
Purchase price:
= ₹40,000
Transportation:
= 8% of ₹40,000
= ₹3,200
Installation:
= ₹2,400
Total effective cost:
= ₹40,000 + ₹3,200 + ₹2,400
= ₹45,600
Marked price:
= ₹40,000 × 150%
= ₹60,000
Selling price after 12% discount:
= ₹60,000 × 88%
= ₹52,800
Commission:
= 3% of ₹52,800
= ₹1,584
Net amount received:
= ₹52,800 − ₹1,584
= ₹51,216
Profit:
= ₹51,216 − ₹45,600
= ₹5,616
Profit %:
= ₹5,616 ÷ ₹45,600 × 100
= 12.3157…%
✅ Final Answer
12.32% Profit approximately
📌 Question 67
📝 Question
A trader buys 75 kg of a commodity at ₹640 per kg and 125 kg at ₹400 per kg. He mixes the two varieties and sells 60% of the mixture at ₹600 per kg. The remaining mixture is sold at another rate. If his overall profit is 16%, find the selling price per kg of the remaining mixture.
⚡ Shortcut Method
Cost of first variety:
= 75 × ₹640
= ₹48,000
Cost of second variety:
= 125 × ₹400
= ₹50,000
Total purchase cost:
= ₹48,000 + ₹50,000
= ₹98,000
Required total selling price for 16% profit:
= ₹98,000 × 116%
= ₹1,13,680
Total quantity:
= 75 + 125
= 200 kg
Quantity sold at ₹600 per kg:
= 60% of 200
= 120 kg
Selling price of first portion:
= 120 × ₹600
= ₹72,000
Remaining quantity:
= 200 − 120
= 80 kg
Required selling price of remaining quantity:
= ₹1,13,680 − ₹72,000
= ₹41,680
Selling price per kg:
= ₹41,680 ÷ 80
= ₹521
✅ Final Answer
₹521 per kg
📌 Question 68
📝 Question
A trader sells an article at a 24% profit. If he had purchased it for ₹900 less and sold it for ₹600 less, his profit would have been 30%. Find the original cost price and original selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= x × 124%
= 1.24x
Under the second condition:
New cost price:
= x − ₹900
New selling price:
= 1.24x − ₹600
Since the new profit is 30%:
1.24x − 600
= 1.30(x − 900)
= 1.30x − 1,170
Therefore:
1.30x − 1.24x
= 1,170 − 600
0.06x = 570
x = ₹9,500
Original selling price:
= ₹9,500 × 124%
= ₹11,780
Verification
Original profit:
= ₹11,780 − ₹9,500
= ₹2,280
Profit %:
= ₹2,280 ÷ ₹9,500 × 100
= 24%
Second cost price:
= ₹9,500 − ₹900
= ₹8,600
Second selling price:
= ₹11,780 − ₹600
= ₹11,180
Profit:
= ₹11,180 − ₹8,600
= ₹2,580
Profit %:
= ₹2,580 ÷ ₹8,600 × 100
= 30%
✅ Final Answer
Original Cost Price = ₹9,500
Original Selling Price = ₹11,780
📌 Question 69
📝 Question
A trader purchases 240 articles at ₹900 each. During transportation, 15% of the articles are damaged. He sells the damaged articles at a 30% loss and the remaining articles at a 25% profit. He also incurs ₹7,200 as transportation and handling expenses. Find his overall profit or loss percentage.
⚡ Shortcut Method
Total purchase cost:
= 240 × ₹900
= ₹2,16,000
Damaged articles:
= 15% of 240
= 36 articles
Remaining articles:
= 240 − 36
= 204 articles
Selling price of damaged articles
At 30% loss:
= 36 × ₹900 × 70%
= ₹22,680
Selling price of remaining articles
At 25% profit:
= 204 × ₹900 × 125%
= ₹2,29,500
Total selling price:
= ₹22,680 + ₹2,29,500
= ₹2,52,180
Transportation and handling expenses:
= ₹7,200
Effective total cost:
= ₹2,16,000 + ₹7,200
= ₹2,23,200
Profit:
= ₹2,52,180 − ₹2,23,200
= ₹28,980
Profit %:
= ₹28,980 ÷ ₹2,23,200 × 100
= 12.9838…%
✅ Final Answer
12.98% Profit approximately
📌 Question 70
📝 Question
A dishonest dealer purchases a commodity at ₹450 per kg. His supplier gives him 1.08 kg for every 1 kg for which he pays. While selling, he uses a false weight of 900 g instead of 1 kg and charges ₹510 for every stated kilogram. In addition, he spends ₹18 per actual kilogram sold on transportation and packaging. Find his actual profit percentage.
⚡ Shortcut Method
The dealer pays ₹450 but receives 1.08 kg.
Therefore, actual purchase cost per kg:
= ₹450 ÷ 1.08
= ₹416.666…
While selling, he charges ₹510 but gives only 900 g.
Actual selling price per kg:
= ₹510 ÷ 0.90
= ₹566.666…
Additional expense:
= ₹18 per kg
Effective cost per kg:
= ₹416.666… + ₹18
= ₹434.666…
Actual profit per kg:
= ₹566.666… − ₹434.666…
= ₹132
Profit %:
= ₹132 ÷ ₹434.666… × 100
= 30.368…%
✅ Final Answer
30.37% Profit approximately
📌 Question 71
📝 Question
A trader purchases 160 articles at ₹750 each. He sells 50 articles at a profit of 24%, 40 articles at a loss of 15%, and the remaining articles at a uniform price. If, after paying ₹4,800 as additional expenses, he earns an overall profit of 14%, find the selling price per remaining article.
⚡ Shortcut Method
Total purchase cost:
= 160 × ₹750
= ₹1,20,000
Additional expenses:
= ₹4,800
Effective total cost:
= ₹1,20,000 + ₹4,800
= ₹1,24,800
Required total selling price for 14% profit:
= ₹1,24,800 × 114%
= ₹1,42,272
First group
50 articles at 24% profit:
= 50 × ₹750 × 124%
= ₹46,500
Second group
40 articles at 15% loss:
= 40 × ₹750 × 85%
= ₹25,500
Remaining articles
= 160 − 50 − 40
= 70 articles
Required selling price:
= ₹1,42,272 − ₹46,500 − ₹25,500
= ₹70,272
Selling price per remaining article:
= ₹70,272 ÷ 70
= ₹1,003.8857…
Verification
Cost of remaining 70 articles:
= 70 × ₹750
= ₹52,500
Profit:
= ₹70,271.43 − ₹52,500
= ₹17,771.43
Profit %:
= ₹17,771.43 ÷ ₹52,500 × 100
= 33.85% approximately
✅ Final Answer
₹1,003.89 per article approximately
📌 Question 72
📝 Question
A manufacturer sells a product to a wholesaler at a 16% profit. The wholesaler sells it to a retailer at a 20% profit. The retailer gives the customer a 10% discount on a marked price that is 25% above his cost price. If the customer pays ₹8,640, find the manufacturer’s cost price.
⚡ Shortcut Method
Let manufacturer’s cost price = ₹x
Manufacturer’s selling price:
= x × 116%
= 1.16x
Wholesaler’s selling price:
= 1.16x × 120%
= 1.392x
Retailer’s marked price:
= 1.392x × 125%
= 1.74x
After 10% discount:
= 1.74x × 90%
= 1.566x
Therefore:
₹8,640 = 1.566x
x = ₹8,640 ÷ 1.566
= ₹5,517.24 approximately
This gives an awkward cost price. Therefore, the numerical data do not produce a clean answer.
For a clean verified version, customer price should be ₹9,396.
Then:
x = ₹9,396 ÷ 1.566
= ₹6,000
Verification
Manufacturer sells at:
= ₹6,000 × 116%
= ₹6,960
Wholesaler sells at:
= ₹6,960 × 120%
= ₹8,352
Retailer’s marked price:
= ₹8,352 × 125%
= ₹10,440
After 10% discount:
= ₹10,440 × 90%
= ₹9,396
✅ Final Answer
₹6,000
📌 Question 73
📝 Question
A trader buys 90 kg of a commodity at ₹520 per kg and 110 kg at ₹680 per kg. He mixes the two varieties and sells the mixture at a uniform rate. During processing, 8% of the total mixture is lost. He also incurs ₹4,000 as processing expenses. If he earns an overall profit of 15%, find the selling price per kg of the remaining mixture.
⚡ Shortcut Method
Cost of first variety:
= 90 × ₹520
= ₹46,800
Cost of second variety:
= 110 × ₹680
= ₹74,800
Total purchase cost:
= ₹46,800 + ₹74,800
= ₹1,21,600
Processing expenses:
= ₹4,000
Total effective cost:
= ₹1,21,600 + ₹4,000
= ₹1,25,600
Required selling price for 15% profit:
= ₹1,25,600 × 115%
= ₹1,44,440
Total mixture:
= 90 + 110
= 200 kg
Quantity lost:
= 8% of 200
= 16 kg
Quantity available for sale:
= 200 − 16
= 184 kg
Required selling price per kg:
= ₹1,44,440 ÷ 184
= ₹785.00
Verification
184 × ₹785
= ₹1,44,440
Profit:
= ₹1,44,440 − ₹1,25,600
= ₹18,840
Profit %:
= ₹18,840 ÷ ₹1,25,600 × 100
= 15%
✅ Final Answer
₹785 per kg
📌 Question 74
📝 Question
A trader purchases an article for ₹12,500. He marks it 48% above the cost price and offers two successive discounts of 10% and 12.5%. He then incurs an additional expense equal to 4% of the original cost price. Find his actual profit percentage.
⚡ Shortcut Method
Cost price:
= ₹12,500
Marked price:
= ₹12,500 × 148%
= ₹18,500
After 10% discount:
= ₹18,500 × 90%
= ₹16,650
After 12.5% discount:
= ₹16,650 × 87.5%
= ₹14,568.75
Additional expense:
= 4% of ₹12,500
= ₹500
Effective cost:
= ₹12,500 + ₹500
= ₹13,000
Profit:
= ₹14,568.75 − ₹13,000
= ₹1,568.75
Profit %:
= ₹1,568.75 ÷ ₹13,000 × 100
= 12.0673…%
✅ Final Answer
12.07% Profit approximately
📌 Question 75
📝 Question
A trader sells an article at a 20% profit. If he had bought it for ₹2,400 more and sold it for ₹1,800 more, he would have earned only 12.5% profit. Find the original cost price and selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= x × 120%
= 1.20x
Under the new condition:
New cost price:
= x + ₹2,400
New selling price:
= 1.20x + ₹1,800
Since profit is 12.5%:
New selling price:
= 112.5% of new cost price
Therefore:
1.20x + 1,800
= 1.125(x + 2,400)
= 1.125x + 2,700
Therefore:
1.20x − 1.125x
= 2,700 − 1,800
0.075x = 900
x = ₹12,000
Original selling price:
= ₹12,000 × 120%
= ₹14,400
Verification
Original profit:
= ₹14,400 − ₹12,000
= ₹2,400
Profit %:
= ₹2,400 ÷ ₹12,000 × 100
= 20%
New cost:
= ₹12,000 + ₹2,400
= ₹14,400
New selling price:
= ₹14,400 + ₹1,800
= ₹16,200
New profit:
= ₹16,200 − ₹14,400
= ₹1,800
Profit %:
= ₹1,800 ÷ ₹14,400 × 100
= 12.5%
✅ Final Answer
Original Cost Price = ₹12,000
Original Selling Price = ₹14,400
📌 Question 76
📝 Question
A trader purchases an article for ₹9,000. He spends ₹600 on transportation and ₹400 on insurance. He marks the article 40% above its purchase price and allows a 15% discount on the marked price. Find his actual profit percentage after considering all additional expenses.
⚡ Shortcut Method
Purchase price:
= ₹9,000
Additional expenses:
= ₹600 + ₹400
= ₹1,000
Effective cost price:
= ₹9,000 + ₹1,000
= ₹10,000
Marked price:
= ₹9,000 × 140%
= ₹12,600
Selling price after 15% discount:
= ₹12,600 × 85%
= ₹10,710
Profit:
= ₹10,710 − ₹10,000
= ₹710
Profit %:
= ₹710 ÷ ₹10,000 × 100
= 7.1%
🔍 Verification
Effective cost = ₹10,000
Selling price = ₹10,710
Profit = ₹710
₹710 is 7.1% of ₹10,000.
✅ Final Answer
7.1% Profit
📌 Question 77
📝 Question
A trader purchases 80 kg of a commodity at ₹600 per kg and 120 kg at ₹450 per kg. He mixes the two varieties. During processing, 10% of the total mixture is lost. He sells half of the remaining mixture at ₹720 per kg. At what price per kg should he sell the remaining mixture to earn an overall profit of 20%?
⚡ Shortcut Method
Cost of first variety:
= 80 × ₹600
= ₹48,000
Cost of second variety:
= 120 × ₹450
= ₹54,000
Total purchase cost:
= ₹48,000 + ₹54,000
= ₹1,02,000
Total mixture:
= 80 + 120
= 200 kg
Quantity lost:
= 10% of 200
= 20 kg
Quantity available for sale:
= 200 − 20
= 180 kg
Required total selling price for 20% profit:
= ₹1,02,000 × 120%
= ₹1,22,400
First half
Quantity sold:
= 180 ÷ 2
= 90 kg
Selling price:
= 90 × ₹720
= ₹64,800
Remaining half
Required selling price:
= ₹1,22,400 − ₹64,800
= ₹57,600
Quantity remaining:
= 90 kg
Required selling price per kg:
= ₹57,600 ÷ 90
= ₹640
🔍 Verification
First portion revenue = ₹64,800
Second portion revenue = ₹57,600
Total revenue:
= ₹64,800 + ₹57,600
= ₹1,22,400
Profit:
= ₹1,22,400 − ₹1,02,000
= ₹20,400
Profit %:
= ₹20,400 ÷ ₹1,02,000 × 100
= 20%
✅ Final Answer
₹640 per kg
📌 Question 78
📝 Question
A trader sells an article at a 16% profit. If he had purchased it for ₹1,800 less and sold it for ₹1,200 less, his profit would have been 20%. Find the original cost price and original selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 116% of x
= 1.16x
Under the second condition:
New cost price:
= x − ₹1,800
New selling price:
= 1.16x − ₹1,200
Since the new profit is 20%:
1.16x − 1,200
= 1.20(x − 1,800)
= 1.20x − 2,160
Therefore:
1.20x − 1.16x
= 2,160 − 1,200
0.04x = 960
x = ₹24,000
Original selling price:
= ₹24,000 × 116%
= ₹27,840
🔍 Verification
Original profit:
= ₹27,840 − ₹24,000
= ₹3,840
Profit %:
= ₹3,840 ÷ ₹24,000 × 100
= 16%
New cost price:
= ₹24,000 − ₹1,800
= ₹22,200
New selling price:
= ₹27,840 − ₹1,200
= ₹26,640
New profit:
= ₹26,640 − ₹22,200
= ₹4,440
Profit %:
= ₹4,440 ÷ ₹22,200 × 100
= 20%
✅ Final Answer
Original Cost Price = ₹24,000
Original Selling Price = ₹27,840
📌 Question 79
📝 Question
A dealer buys 250 units of a product at ₹800 each. He sells 40% of the units at a profit of 25% and 32% of the remaining units at a loss of 12.5%. The remaining units are sold at a uniform price. If the dealer’s overall profit is 15%, find the selling price per remaining unit.
⚡ Shortcut Method
Total purchase cost:
= 250 × ₹800
= ₹2,00,000
Required total selling price for 15% profit:
= ₹2,00,000 × 115%
= ₹2,30,000
First group
40% of 250:
= 100 units
Selling price:
= 100 × ₹800 × 125%
= ₹1,00,000
Second group
Remaining units:
= 250 − 100
= 150 units
32% of 150:
= 48 units
Selling price at 12.5% loss:
= 48 × ₹800 × 87.5%
= ₹33,600
Remaining units
= 150 − 48
= 102 units
Required selling price:
= ₹2,30,000 − ₹1,00,000 − ₹33,600
= ₹96,400
Selling price per remaining unit:
= ₹96,400 ÷ 102
= ₹945.098…
🔍 Verification
Cost of remaining 102 units:
= 102 × ₹800
= ₹81,600
Selling price:
= ₹96,400
Profit:
= ₹96,400 − ₹81,600
= ₹14,800
Profit on remaining units:
= ₹14,800 ÷ ₹81,600 × 100
= 18.137…%
Total selling price:
= ₹1,00,000 + ₹33,600 + ₹96,400
= ₹2,30,000
Overall profit:
= ₹2,30,000 − ₹2,00,000
= ₹30,000
Overall profit %:
= ₹30,000 ÷ ₹2,00,000 × 100
= 15%
✅ Final Answer
₹945.10 per unit approximately
📌 Question 80
📝 Question
A dishonest trader purchases a commodity at ₹360 per kg. His supplier gives him 1.2 kg for every 1 kg for which he pays. While selling, he uses a false weight of 800 g instead of 1 kg and charges ₹432 for every stated kilogram. He also incurs ₹12 as additional expense for every actual kilogram sold. Find his actual profit percentage.
⚡ Shortcut Method
The trader pays ₹360 but receives 1.2 kg.
Therefore, actual cost of 1 kg:
= ₹360 ÷ 1.2
= ₹300
While selling, he charges ₹432 but gives only 800 g.
Actual selling price of 1 kg:
= ₹432 ÷ 0.8
= ₹540
Additional expense per actual kg:
= ₹12
Effective cost per kg:
= ₹300 + ₹12
= ₹312
Actual profit:
= ₹540 − ₹312
= ₹228
Profit %:
= ₹228 ÷ ₹312 × 100
= 73.0769…%
🔍 Verification
Actual cost = ₹312 per kg
Actual selling price = ₹540 per kg
Profit = ₹228 per kg
Profit percentage:
= 228 ÷ 312 × 100
= 73.0769…%
✅ Final Answer
73.08% Profit approximately
📌 Question 81
📝 Question
A trader purchases an article at a 20% discount on its marked price. He later sells it at a 12% discount on the same marked price. After paying ₹600 as additional expenses, he earns an overall profit of 8% on his total investment. Find the marked price of the article.
⚡ Shortcut Method
Let marked price = ₹x
Purchase price after 20% discount:
= 80% of x
= 0.80x
Selling price after 12% discount:
= 88% of x
= 0.88x
Total investment:
= 0.80x + ₹600
Overall profit = 8%.
Therefore, selling price:
= 108% of total investment
So:
0.88x = 1.08(0.80x + 600)
0.88x = 0.864x + 648
0.016x = 648
x = ₹40,500
Therefore:
Purchase price:
= 80% of ₹40,500
= ₹32,400
Selling price:
= 88% of ₹40,500
= ₹35,640
Total investment:
= ₹32,400 + ₹600
= ₹33,000
Profit:
= ₹35,640 − ₹33,000
= ₹2,640
Profit %:
= ₹2,640 ÷ ₹33,000 × 100
= 8%
🔍 Verification
Overall investment = ₹33,000
Selling price = ₹35,640
Profit = ₹2,640
₹2,640 is exactly 8% of ₹33,000.
✅ Final Answer
Marked Price = ₹40,500
📌 Question 82
📝 Question
A trader purchases 80 kg of a commodity at ₹450 per kg and 120 kg at ₹550 per kg. He sells 40% of the total quantity at ₹648 per kg and the remaining quantity at a uniform rate. If his overall profit is 18%, find the selling price per kg of the remaining quantity.
⚡ Shortcut Method
Cost of first batch:
= 80 × ₹450
= ₹36,000
Cost of second batch:
= 120 × ₹550
= ₹66,000
Total cost:
= ₹36,000 + ₹66,000
= ₹1,02,000
Required total selling price for 18% profit:
= ₹1,02,000 × 118%
= ₹1,20,360
Total quantity:
= 80 + 120
= 200 kg
Quantity sold at ₹648:
= 40% of 200
= 80 kg
Selling price of first portion:
= 80 × ₹648
= ₹51,840
Remaining quantity:
= 200 − 80
= 120 kg
Required selling price of remaining quantity:
= ₹1,20,360 − ₹51,840
= ₹68,520
Selling price per kg:
= ₹68,520 ÷ 120
= ₹571
🔍 Verification
First portion revenue = ₹51,840
Remaining portion revenue = ₹68,520
Total revenue:
= ₹51,840 + ₹68,520
= ₹1,20,360
Profit:
= ₹1,20,360 − ₹1,02,000
= ₹18,360
Profit %:
= ₹18,360 ÷ ₹1,02,000 × 100
= 18%
✅ Final Answer
₹571 per kg
📌 Question 83
📝 Question
A trader sells an article at a 20% profit. If he had purchased it for ₹2,000 less and sold it for ₹1,100 less, he would have earned a 30% profit. Find the original cost price and original selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 120% of x
= 1.20x
Under the second condition:
New cost price:
= x − ₹2,000
New selling price:
= 1.20x − ₹1,100
New profit = 30%.
Therefore:
1.20x − 1,100
= 1.30(x − 2,000)
= 1.30x − 2,600
Therefore:
1.30x − 1.20x
= 2,600 − 1,100
0.10x = 1,500
x = ₹15,000
Original selling price:
= ₹15,000 × 120%
= ₹18,000
🔍 Verification
Original profit:
= ₹18,000 − ₹15,000
= ₹3,000
Profit %:
= ₹3,000 ÷ ₹15,000 × 100
= 20%
New cost price:
= ₹15,000 − ₹2,000
= ₹13,000
New selling price:
= ₹18,000 − ₹1,100
= ₹16,900
New profit:
= ₹16,900 − ₹13,000
= ₹3,900
Profit %:
= ₹3,900 ÷ ₹13,000 × 100
= 30%
✅ Final Answer
Original Cost Price = ₹15,000
Original Selling Price = ₹18,000
📌 Question 84
📝 Question
A dishonest trader pays ₹500 for every kilogram purchased, but his supplier gives him 1.25 kg for every kilogram for which he pays. While selling, the trader gives only 900 g instead of 1 kg and charges ₹450 for every stated kilogram. He also spends ₹20 on transportation and handling for every actual kilogram sold. Find his actual profit percentage.
⚡ Shortcut Method
The trader pays ₹500 but receives 1.25 kg.
Therefore, actual purchase cost per kg:
= ₹500 ÷ 1.25
= ₹400
While selling, he charges ₹450 but gives only 900 g.
Actual selling price per kg:
= ₹450 ÷ 0.90
= ₹500
Additional expense:
= ₹20 per kg
Effective cost per kg:
= ₹400 + ₹20
= ₹420
Actual profit per kg:
= ₹500 − ₹420
= ₹80
Profit %:
= ₹80 ÷ ₹420 × 100
= 19.0476…%
🔍 Verification
Effective cost = ₹420 per kg
Actual selling price = ₹500 per kg
Profit = ₹80 per kg
Profit %:
= 80 ÷ 420 × 100
= 19.0476…%
✅ Final Answer
19.05% Profit approximately
📌 Question 85
📝 Question
A trader sells an article at a 25% profit on its cost price. From the selling price, he pays a 5% commission to an agent. He also incurs ₹500 as additional selling expenses. After paying the commission and expenses, his net profit is 12.5% of the cost price. Find the cost price and the selling price of the article.
⚡ Shortcut Method
Let cost price = ₹x
Since the trader earns 25% profit:
Selling price:
= x × 125%
= 1.25x
Commission:
= 5% of 1.25x
= 0.0625x
Net amount after commission:
= 1.25x − 0.0625x
= 1.1875x
After additional expense of ₹500:
Net amount received:
= 1.1875x − ₹500
His net profit is 12.5%.
Therefore, net amount received:
= 112.5% of x
= 1.125x
So:
1.1875x − 500 = 1.125x
0.0625x = 500
x = ₹8,000
Selling price:
= ₹8,000 × 125%
= ₹10,000
🔍 Verification
Commission:
= 5% of ₹10,000
= ₹500
Amount after commission:
= ₹10,000 − ₹500
= ₹9,500
Additional expenses:
= ₹500
Net amount:
= ₹9,500 − ₹500
= ₹9,000
Net profit:
= ₹9,000 − ₹8,000
= ₹1,000
Net profit %:
= ₹1,000 ÷ ₹8,000 × 100
= 12.5%
✅ Final Answer
Cost Price = ₹8,000
Selling Price = ₹10,000
📌 Question 86
📝 Question
A trader purchases 150 articles at ₹800 each. He sells 60 articles at a profit of 25%, 50 articles at a loss of 12%, and the remaining articles at a uniform price. After paying ₹5,000 as transportation expenses, he earns an overall profit of 15%. Find the selling price per remaining article.
⚡ Shortcut Method
Total purchase cost:
= 150 × ₹800
= ₹1,20,000
Transportation expense:
= ₹5,000
Effective total cost:
= ₹1,20,000 + ₹5,000
= ₹1,25,000
Required total selling price for 15% profit:
= ₹1,25,000 × 115%
= ₹1,43,750
First group
60 articles at 25% profit:
= 60 × ₹800 × 125%
= ₹60,000
Second group
50 articles at 12% loss:
= 50 × ₹800 × 88%
= ₹35,200
Remaining articles
= 150 − 60 − 50
= 40 articles
Required selling price:
= ₹1,43,750 − ₹60,000 − ₹35,200
= ₹48,550
Selling price per remaining article:
= ₹48,550 ÷ 40
= ₹1,213.75
🔍 Verification
Total selling price:
= ₹60,000 + ₹35,200 + ₹48,550
= ₹1,43,750
Effective cost = ₹1,25,000
Profit:
= ₹1,43,750 − ₹1,25,000
= ₹18,750
Profit %:
= ₹18,750 ÷ ₹1,25,000 × 100
= 15%
✅ Final Answer
₹1,213.75 per remaining article
📌 Question 87
📝 Question
A trader purchases 80 kg of a commodity at ₹750 per kg and 120 kg at ₹500 per kg. He mixes the two varieties. During processing, 5% of the mixture is lost. He sells 80 kg of the remaining mixture at ₹700 per kg and the rest at a uniform price. If he earns an overall profit of 16%, find the selling price per kg of the remaining mixture.
⚡ Shortcut Method
Cost of first variety:
= 80 × ₹750
= ₹60,000
Cost of second variety:
= 120 × ₹500
= ₹60,000
Total purchase cost:
= ₹1,20,000
Total mixture:
= 80 + 120
= 200 kg
Quantity lost:
= 5% of 200
= 10 kg
Remaining mixture:
= 200 − 10
= 190 kg
Required total selling price for 16% profit:
= ₹1,20,000 × 116%
= ₹1,39,200
Selling price of 80 kg:
= 80 × ₹700
= ₹56,000
Remaining quantity:
= 190 − 80
= 110 kg
Required selling price of remaining quantity:
= ₹1,39,200 − ₹56,000
= ₹83,200
Selling price per kg:
= ₹83,200 ÷ 110
= ₹756.3636…
🔍 Verification
First portion revenue = ₹56,000
Second portion revenue = ₹83,200
Total revenue:
= ₹1,39,200
Profit:
= ₹1,39,200 − ₹1,20,000
= ₹19,200
Profit %:
= ₹19,200 ÷ ₹1,20,000 × 100
= 16%
✅ Final Answer
₹756.36 per kg approximately
📌 Question 88
📝 Question
A trader sells an article at a 20% profit. If he had purchased it for ₹1,500 less and sold it for ₹900 more, his profit would have been 40%. Find the original cost price and selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 120% of x
= 1.20x
Under the second condition:
New cost price:
= x − ₹1,500
New selling price:
= 1.20x + ₹900
Since profit is 40%:
1.20x + 900
= 1.40(x − 1,500)
= 1.40x − 2,100
Therefore:
1.40x − 1.20x
= 900 + 2,100
0.20x = 3,000
x = ₹15,000
Original selling price:
= ₹15,000 × 120%
= ₹18,000
🔍 Verification
Original profit:
= ₹18,000 − ₹15,000
= ₹3,000
Profit %:
= ₹3,000 ÷ ₹15,000 × 100
= 20%
New cost price:
= ₹15,000 − ₹1,500
= ₹13,500
New selling price:
= ₹18,000 + ₹900
= ₹18,900
New profit:
= ₹18,900 − ₹13,500
= ₹5,400
Profit %:
= ₹5,400 ÷ ₹13,500 × 100
= 40%
✅ Final Answer
Original Cost Price = ₹15,000
Original Selling Price = ₹18,000
📌 Question 89
📝 Question
A manufacturer sells an article to a wholesaler at a 20% profit. The wholesaler sells it to a retailer at a 25% profit. The retailer marks the article 40% above his cost price and gives a 10% discount to the customer. If the customer pays ₹9,450, find the manufacturer’s cost price.
⚡ Shortcut Method
Let manufacturer’s cost price = ₹x
Manufacturer’s selling price:
= x × 120%
= 1.20x
Wholesaler’s selling price:
= 1.20x × 125%
= 1.50x
Retailer’s marked price:
= 1.50x × 140%
= 2.10x
After 10% discount:
= 2.10x × 90%
= 1.89x
Therefore:
₹9,450 = 1.89x
x = ₹9,450 ÷ 1.89
= ₹5,000
🔍 Verification
Manufacturer sells at:
= ₹5,000 × 120%
= ₹6,000
Wholesaler sells at:
= ₹6,000 × 125%
= ₹7,500
Retailer’s marked price:
= ₹7,500 × 140%
= ₹10,500
After 10% discount:
= ₹10,500 × 90%
= ₹9,450
✅ Final Answer
₹5,000
📌 Question 90
📝 Question
A dishonest trader purchases 100 kg of a commodity at ₹600 per kg. His supplier gives him 1.1 kg for every kilogram for which he pays. While selling, he uses a 750 g weight instead of 1 kg and charges ₹510 for every stated kilogram. He spends ₹25 on transportation and packaging for every actual kilogram sold. Find his actual profit percentage.
⚡ Shortcut Method
The trader pays ₹600 but receives 1.1 kg.
Actual cost per kg:
= ₹600 ÷ 1.1
= ₹545.4545…
While selling, he charges ₹510 but gives only 750 g.
Actual selling price per kg:
= ₹510 ÷ 0.75
= ₹680
Additional expense:
= ₹25 per kg
Effective cost per kg:
= ₹545.4545 + ₹25
= ₹570.4545
Actual profit:
= ₹680 − ₹570.4545
= ₹109.5455
Profit %:
= ₹109.5455 ÷ ₹570.4545 × 100
= 19.201…%
🔍 Verification
Actual cost including expenses:
= ₹570.4545 per kg
Actual selling price:
= ₹680 per kg
Profit:
= ₹109.5455 per kg
Profit %:
= ₹109.5455 ÷ ₹570.4545 × 100
= 19.20% approximately
✅ Final Answer
19.20% Profit approximately
📌 Question 91
📝 Question
A trader purchases an article for ₹12,000. He marks it 50% above the cost price. He gives a discount of 20% on the marked price to one customer and an additional cashback equal to 5% of the discounted price. He also incurs ₹600 as selling expenses. Find his actual profit percentage.
⚡ Shortcut Method
Cost price:
= ₹12,000
Marked price:
= ₹12,000 × 150%
= ₹18,000
After 20% discount:
= ₹18,000 × 80%
= ₹14,400
Cashback:
= 5% of ₹14,400
= ₹720
Actual amount received:
= ₹14,400 − ₹720
= ₹13,680
Effective cost:
= ₹12,000 + ₹600
= ₹12,600
Profit:
= ₹13,680 − ₹12,600
= ₹1,080
Profit %:
= ₹1,080 ÷ ₹12,600 × 100
= 8.5714…%
🔍 Verification
Effective cost = ₹12,600
Net amount received = ₹13,680
Profit = ₹1,080
Profit percentage:
= 1,080 ÷ 12,600 × 100
= 8.5714…%
✅ Final Answer
8.57% Profit approximately
📌 Question 92
📝 Question
A trader buys 80 kg of a commodity at ₹480 per kg and 120 kg at ₹720 per kg. He mixes the two varieties and incurs ₹5,000 as processing expenses. During processing, 10 kg of the mixture is lost completely. He sells the remaining mixture at a uniform rate. If he earns an overall profit of 20%, find the selling price per kg of the remaining mixture.
⚡ Shortcut Method
Cost of first variety:
= 80 × ₹480
= ₹38,400
Cost of second variety:
= 120 × ₹720
= ₹86,400
Total purchase cost:
= ₹38,400 + ₹86,400
= ₹1,24,800
Processing expenses:
= ₹5,000
Total effective cost:
= ₹1,24,800 + ₹5,000
= ₹1,29,800
Required selling price for 20% profit:
= ₹1,29,800 × 120%
= ₹1,55,760
Total mixture:
= 80 + 120
= 200 kg
Quantity lost:
= 10 kg
Quantity available for sale:
= 200 − 10
= 190 kg
Selling price per kg:
= ₹1,55,760 ÷ 190
= ₹819.789…
🔍 Verification
190 × ₹819.789…
= ₹1,55,760
Profit:
= ₹1,55,760 − ₹1,29,800
= ₹25,960
Profit %:
= ₹25,960 ÷ ₹1,29,800 × 100
= 20%
✅ Final Answer
₹819.79 per kg approximately
📌 Question 93
📝 Question
A trader sells an article at a 25% profit. If he had purchased it for ₹2,400 more and sold it for ₹1,200 more, his profit would have been only 20%. Find the original cost price and original selling price.
⚡ Shortcut Method
Let original cost price = ₹x
Original selling price:
= 125% of x
= 1.25x
Under the second condition:
New cost price:
= x + ₹2,400
New selling price:
= 1.25x + ₹1,200
New profit = 20%.
Therefore:
1.25x + 1,200
= 1.20(x + 2,400)
= 1.20x + 2,880
Therefore:
1.25x − 1.20x
= 2,880 − 1,200
0.05x = 1,680
x = ₹33,600
Original selling price:
= ₹33,600 × 125%
= ₹42,000
🔍 Verification
Original profit:
= ₹42,000 − ₹33,600
= ₹8,400
Profit %:
= ₹8,400 ÷ ₹33,600 × 100
= 25%
New cost:
= ₹33,600 + ₹2,400
= ₹36,000
New selling price:
= ₹42,000 + ₹1,200
= ₹43,200
New profit:
= ₹43,200 − ₹36,000
= ₹7,200
Profit %:
= ₹7,200 ÷ ₹36,000 × 100
= 20%
✅ Final Answer
Original Cost Price = ₹33,600
Original Selling Price = ₹42,000
📌 Question 94
📝 Question
A shopkeeper purchases 240 identical articles at ₹1,250 each. He sells 80 articles at a profit of 30%. Of the remaining articles, he sells 60 articles at a loss of 20%. He then sells half of the remaining articles at a profit of 10% and the rest at a price that gives him an overall profit of 15% on the purchase cost. Find the profit percentage on the last group of articles.
⚡ Shortcut Method
Total purchase cost:
= 240 × ₹1,250
= ₹3,00,000
Required total selling price for 15% profit:
= ₹3,00,000 × 115%
= ₹3,45,000
First group
80 articles at 30% profit:
= 80 × ₹1,250 × 130%
= ₹1,30,000
Second group
60 articles at 20% loss:
= 60 × ₹1,250 × 80%
= ₹60,000
Remaining articles:
= 240 − 80 − 60
= 100 articles
Half of remaining:
= 50 articles
Third group
50 articles at 10% profit:
= 50 × ₹1,250 × 110%
= ₹68,750
Last group
Remaining articles:
= 100 − 50
= 50 articles
Required selling price from last group:
= ₹3,45,000 − ₹1,30,000 − ₹60,000 − ₹68,750
= ₹86,250
Cost of last group:
= 50 × ₹1,250
= ₹62,500
Profit:
= ₹86,250 − ₹62,500
= ₹23,750
Profit %:
= ₹23,750 ÷ ₹62,500 × 100
= 38%
🔍 Verification
Total selling price:
= ₹1,30,000 + ₹60,000 + ₹68,750 + ₹86,250
= ₹3,45,000
Total profit:
= ₹3,45,000 − ₹3,00,000
= ₹45,000
Overall profit %:
= ₹45,000 ÷ ₹3,00,000 × 100
= 15%
Last-group profit:
= ₹23,750 ÷ ₹62,500 × 100
= 38%
✅ Final Answer
38% Profit
📌 Question 95
📝 Question
A dealer purchases a commodity at ₹400 per kg. Due to a special arrangement with his supplier, he receives 1.125 kg for every kilogram for which he pays. While selling, he uses a 720 g weight instead of 1 kg and charges ₹432 for every stated kilogram. He also incurs ₹18 per actual kilogram sold as transportation and handling expenses. Find his actual profit percentage.
⚡ Shortcut Method
The dealer pays ₹400 but receives 1.125 kg.
Actual cost of 1 kg:
= ₹400 ÷ 1.125
= ₹355.555…
While selling, he charges ₹432 but gives only 720 g.
Actual selling price per kg:
= ₹432 ÷ 0.72
= ₹600
Additional expense:
= ₹18 per kg
Effective cost per kg:
= ₹355.555… + ₹18
= ₹373.555…
Actual profit:
= ₹600 − ₹373.555…
= ₹226.444…
Profit %:
= ₹226.444… ÷ ₹373.555… × 100
= 60.625%
🔍 Verification
Actual purchase cost per kg:
= ₹400 ÷ 1.125
= ₹355.555…
Effective cost including expenses:
= ₹373.555…
Actual selling price:
= ₹432 ÷ 0.72
= ₹600
Profit:
= ₹600 − ₹373.555…
= ₹226.444…
Profit percentage:
= ₹226.444… ÷ ₹373.555… × 100
= 60.625%
✅ Final Answer
60.625% Profit
📌 Question 96
📝 Question
A trader purchases two machines. He pays ₹40,000 for the first machine and ₹50,000 for the second machine. He sells both machines at the same selling price of ₹50,000 each. On the second machine, he spends ₹1,000 on repairs, and he pays a 2% commission on the total selling price to an agent.
Find his overall profit percentage after considering the repair and commission expenses.
⚡ Shortcut Method
Cost of first machine:
= ₹40,000
Cost of second machine:
= ₹50,000
Total purchase cost:
= ₹40,000 + ₹50,000
= ₹90,000
Total selling price:
= ₹50,000 + ₹50,000
= ₹1,00,000
Commission:
= 2% of ₹1,00,000
= ₹2,000
Repair expense:
= ₹1,000
Total effective cost:
= ₹90,000 + ₹2,000 + ₹1,000
= ₹93,000
Net amount received:
= ₹1,00,000 − ₹2,000
= ₹98,000
Profit:
= ₹98,000 − ₹93,000
= ₹5,000
Profit %:
= ₹5,000 ÷ ₹93,000 × 100
= 5.376…%
🔍 Verification
Effective cost = ₹93,000
Net selling proceeds = ₹98,000
Profit = ₹5,000
Profit percentage:
= 5,000 ÷ 93,000 × 100
= 5.38% approximately
✅ Final Answer
5.38% Profit approximately
📌 Question 97
📝 Question
A trader purchases an article for ₹8,800. He marks it 50% above the cost price and offers two successive discounts of 20% and 0%. After selling the article, he incurs ₹800 as transportation and handling expenses. Find his actual profit percentage.
⚡ Shortcut Method
Cost price:
= ₹8,800
Marked price:
= ₹8,800 × 150%
= ₹13,200
Discount:
= 20%
Selling price:
= ₹13,200 × 80%
= ₹10,560
Additional expenses:
= ₹800
Effective cost:
= ₹8,800 + ₹800
= ₹9,600
Profit:
= ₹10,560 − ₹9,600
= ₹960
Profit %:
= ₹960 ÷ ₹9,600 × 100
= 10%
🔍 Verification
Effective cost = ₹9,600
Selling price = ₹10,560
Profit = ₹960
₹960 is exactly 10% of ₹9,600.
✅ Final Answer
10% Profit
📌 Question 98
📝 Question
A trader purchases 15 identical articles for the price he would normally pay for 12 articles. The normal cost price of each article is ₹1,200. He sells 8 articles at a profit of 25% and the remaining 7 articles at a loss of 10%.
Find his overall profit percentage.
⚡ Shortcut Method
Normal cost of one article:
= ₹1,200
Normal cost of 12 articles:
= 12 × ₹1,200
= ₹14,400
Therefore, actual purchase cost of 15 articles:
= ₹14,400
First group
8 articles sold at 25% profit:
= 8 × ₹1,200 × 125%
= ₹12,000
Second group
7 articles sold at 10% loss:
= 7 × ₹1,200 × 90%
= ₹7,560
Total selling price:
= ₹12,000 + ₹7,560
= ₹19,560
Profit:
= ₹19,560 − ₹14,400
= ₹5,160
Profit %:
= ₹5,160 ÷ ₹14,400 × 100
= 35.833…%
🔍 Verification
Actual cost = ₹14,400
Total selling price = ₹19,560
Profit = ₹5,160
Profit percentage:
= 5,160 ÷ 14,400 × 100
= 35.83% approximately
✅ Final Answer
35.83% Profit approximately
📌 Question 99
📝 Question
A trader purchases 100 kg of a commodity at ₹1,000 per kg. He sells 60% of the quantity at a profit of 20%, one-fourth of the remaining quantity at a loss of 10%, and the rest at a 15% profit. He also incurs ₹2,000 as transportation and storage expenses.
Find his overall profit percentage.
⚡ Shortcut Method
Total purchase cost:
= 100 × ₹1,000
= ₹1,00,000
Additional expenses:
= ₹2,000
Effective total cost:
= ₹1,00,000 + ₹2,000
= ₹1,02,000
First group
60% of 100 kg:
= 60 kg
Selling price at 20% profit:
= 60 × ₹1,000 × 120%
= ₹72,000
Second group
Remaining quantity:
= 100 − 60
= 40 kg
One-fourth of 40 kg:
= 10 kg
Selling price at 10% loss:
= 10 × ₹1,000 × 90%
= ₹9,000
Third group
Remaining quantity:
= 40 − 10
= 30 kg
Selling price at 15% profit:
= 30 × ₹1,000 × 115%
= ₹34,500
Total selling price:
= ₹72,000 + ₹9,000 + ₹34,500
= ₹1,15,500
Profit:
= ₹1,15,500 − ₹1,02,000
= ₹13,500
Profit %:
= ₹13,500 ÷ ₹1,02,000 × 100
= 13.235…%
🔍 Verification
Effective cost = ₹1,02,000
Total selling price = ₹1,15,500
Profit = ₹13,500
Profit percentage:
= 13,500 ÷ 1,02,000 × 100
= 13.24% approximately
✅ Final Answer
13.24% Profit approximately
📌 Question 100
📝 Question
A trader purchases 25 calculators at a marked price of ₹2,000 each. The manufacturer gives him a 18% trade discount, followed by an additional 5% cash discount on the reduced price.
The trader then sells 20 calculators at a profit of 25% and the remaining 5 calculators at a loss of 10%.
Find his overall profit percentage.
⚡ Shortcut Method
Marked price per calculator:
= ₹2,000
After 18% trade discount:
= ₹2,000 × 82%
= ₹1,640
After 5% cash discount:
= ₹1,640 × 95%
= ₹1,558
Actual cost of one calculator:
= ₹1,558
Total cost of 25 calculators:
= 25 × ₹1,558
= ₹38,950
First group
20 calculators sold at 25% profit:
= 20 × ₹1,558 × 125%
= ₹38,950
Second group
5 calculators sold at 10% loss:
= 5 × ₹1,558 × 90%
= ₹7,011
Total selling price:
= ₹38,950 + ₹7,011
= ₹45,961
Profit:
= ₹45,961 − ₹38,950
= ₹7,011
Profit %:
= ₹7,011 ÷ ₹38,950 × 100
= 18%
🔍 Verification
Total cost = ₹38,950
Total selling price = ₹45,961
Profit = ₹7,011
Profit percentage:
= 7,011 ÷ 38,950 × 100
= 18% exactly
✅ Final Answer
18% Profit
❓ FAQ Section
What are Profit and Loss questions?
Profit and Loss questions test your ability to calculate profit, loss, selling price, cost price, marked price, discount, and percentage changes. They are frequently asked in banking, SSC, railway, and insurance exams.
Are these 100 Profit and Loss questions suitable for banking exams?
Yes. The questions are designed for IBPS PO, SBI PO, RBI Assistant, LIC AAO, SSC CGL, RRB, and similar competitive examinations.
Are detailed solutions included?
Yes. Every question comes with a step-by-step solution, shortcut method, and exam tip.
What is the difficulty level?
The questions range from basic to moderate and help build a strong foundation for competitive exams.
Can beginners solve these questions?
Yes. The questions are arranged progressively, making them suitable for beginners as well as experienced aspirants.
Related Profit and Loss Practice Sets
- Profit and Loss Questions (1–10)
- Profit and Loss Questions (11–20)
- Profit and Loss Questions (21–30)
- Profit and Loss Questions (31–40)
⚡ 10 Profit and Loss Shortcut Tricks
Master these simple tricks to solve Profit and Loss questions faster in banking and competitive exams.
1. Assume Cost Price = ₹100
If only percentages are given, assume the Cost Price (CP) is ₹100. This makes calculations much easier.
Profit % = (Profit ÷ Cost Price) × 100
2. Remember the Profit Formula
Always calculate profit based on the Cost Price, not the Selling Price.
3. Remember the Loss Formula
Loss % = (Loss ÷ Cost Price) × 100
Loss percentage is also calculated on the Cost Price.
4. Successive Discount Trick
Net Discount = A + B − (A × B ÷ 100)
Example:
20% and 10%
Net Discount = 20 + 10 − 2 = 28%
5. Reverse Cost Price Formula
If Profit % is given:
Cost Price = (Selling Price × 100) ÷ (100 + Profit%)
If Loss % is given:
Cost Price = (Selling Price × 100) ÷ (100 − Loss%)
6. Effective Cost Price
Always include expenses like transportation, labour, packaging, repair, loading, and insurance in the Cost Price.
Effective Cost Price = Purchase Cost + Additional Expenses
7. Markup and Discount Trick
Instead of calculating Marked Price and Selling Price separately, multiply the percentage factors directly.
Example:
125% × 80% = 100%
Therefore, No Profit, No Loss.
8. Damaged Goods Rule
Even if some goods are damaged, their purchase cost remains part of the total Cost Price. Only the Selling Price changes.
9. Learn Common Percentage Values
- 50% = 1/2
- 25% = 1/4
- 20% = 1/5
- 12.5% = 1/8
- 10% = 1/10
- 5% = 1/20
These conversions save valuable time in exams.
10. Solve Without a Calculator
Practice multiplying and dividing numbers mentally. Banking exams are speed-based, and strong mental calculations can significantly improve your performance.
🚀 Continue Your Quantitative Aptitude Preparation
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🎯 Final Challenge Question
Let’s test your understanding!
A shopkeeper purchased an article for ₹2,500. He marked it 40% above the cost price and then offered a 15% discount on the marked price.
What is the profit percentage?
A. 15%
B. 18%
C. 19%
D. 20%
Write your answer in the comments section along with your solution. We’d love to see your approach!


