Profit and Loss Questions with Answers (Questions 111–120) | Banking Exam Practice Set – Part 12

Profit and Loss Questions with Answers Part 12 featuring Banking Exam aptitude problems, profit percentage calculations, effective cost price, discounts, and shortcut methods.
Practice Profit and Loss Questions (111–120) with shortcut solutions for IBPS PO, SBI PO, SSC CGL, RBI Assistant, LIC AAO, and other competitive exams on BrainQuro.

✍️ Introduction

Welcome to Part 12 of the Profit and Loss Questions with Answers series on BrainQuro. This practice set contains Questions 111–120, carefully designed for aspirants preparing for IBPS PO, SBI PO, RBI Assistant, LIC AAO, SSC CGL, RRB, NIACL AO, UIIC AO, and other competitive examinations.

This set follows the latest Banking Mains pattern and includes advanced concepts such as effective cost price, transportation and insurance charges, damaged goods, agent commission, online marketplace commission, successive discounts, cashback offers, clearance sales, and target overall profit.

Each question is accompanied by a quick shortcut method that helps you solve problems efficiently during exams. Attempt every question yourself before checking the solution to maximize your learning and improve your calculation speed.

📌 Question 111

📝 Question

A wholesaler purchased 800 LED bulbs at ₹180 each. He spent ₹8,000 on transportation and ₹4,000 on insurance. During transit, 40 bulbs were damaged and sold at 50% of their effective cost price. At what percentage profit on the effective cost price should the remaining bulbs be sold so that the wholesaler earns an overall profit of 18%?

⚡ Shortcut Method

Purchase Cost = 800 × 180 = ₹1,44,000

Effective CP = 1,44,000 + 8,000 + 4,000 = ₹1,56,000

Effective CP per Bulb = 1,56,000 ÷ 800 = ₹195

Required Total SP = 1,56,000 × 118% = ₹1,84,080

SP of Damaged Bulbs = 40 × (195 × 50%) = ₹3,900

Required SP of Remaining Bulbs = 1,84,080 − 3,900 = ₹1,80,180

SP per Remaining Bulb = 1,80,180 ÷ 760 = ₹237.08

Profit % = ((237.08 − 195) ÷ 195) × 100

= 21.58%

✅ Final Answer

21.58% Profit


📌 Question 112

📝 Question

A retailer marks an article 200% above its cost price. He allows successive discounts of 20%, 15%, and 10%. After the sale, he gives a cashback equal to 5% of the billed amount. Find his overall profit percentage.

⚡ Shortcut Method

Assume CP = ₹100

MP = ₹300

Final SP = 300 × 0.80 × 0.85 × 0.90 × 0.95

= ₹174.42

Profit = 174.42 − 100

= ₹74.42

Profit %

= 74.42%

✅ Final Answer

74.42% Profit


📌 Question 113

📝 Question

A grocery shopkeeper buys wheat at ₹48 per kg. His weighing machine delivers only 960 g instead of 1 kg. To attract customers, he sells wheat at 4% below the market price of ₹55 per kg. Find his actual profit percentage.

⚡ Shortcut Method

Selling Price = 55 × 96%

= ₹52.80

Actual Cost of 960 g = 48 × 0.96

= ₹46.08

Profit = 52.80 − 46.08

= ₹6.72

Profit % = (6.72 ÷ 46.08) × 100

= 14.58%

✅ Final Answer

14.58% Profit

📌 Question 114

📝 Question

A furniture dealer purchased 250 study tables at ₹3,200 each. He spent ₹25,000 on transportation, ₹15,000 on installation, and ₹10,000 on insurance. During unloading, 10 tables were damaged and sold at 60% of their effective cost price. The remaining tables were sold through an agent who charged 5% commission on the selling price. If the dealer earned an overall profit of 20%, find the selling price of each good table.

⚡ Shortcut Method

Purchase Cost = 250 × 3200 = ₹8,00,000

Effective CP = 8,00,000 + 25,000 + 15,000 + 10,000 = ₹8,50,000

Effective CP per Table = 8,50,000 ÷ 250 = ₹3,400

Required Net SP = 8,50,000 × 120% = ₹10,20,000

Recovery from Damaged Tables = 10 × (3400 × 60%) = ₹20,400

Net Amount Required from Good Tables

= 10,20,000 − 20,400

= ₹9,99,600

Let SP of each good table = ₹x

After 5% commission,

240 × 95% × x = 9,99,600

x = 9,99,600 ÷ (240 × 0.95)

= ₹4,384.21

✅ Final Answer

₹4,384.21 per table


📌 Question 115

📝 Question

A retailer marked an article 150% above its cost price. He offered successive discounts of 20% and 10%, followed by a coupon discount of ₹120. If the customer finally paid ₹2,580, find the cost price of the article.

⚡ Shortcut Method

Final SP before Coupon

= 2,580 + 120

= ₹2,700

After Discounts,

MP × 80% × 90% = 2,700

MP = 2,700 ÷ 0.72

= ₹3,750

Since MP = 250% of CP,

CP = 3,750 ÷ 2.5

= ₹1,500

✅ Final Answer

₹1,500


📌 Question 116

📝 Question

A wholesaler purchased 600 mixer grinders at ₹1,800 each. He spent ₹36,000 on freight and ₹24,000 on insurance. During transportation, 30 grinders were damaged and sold at 25% below their effective cost price. The remaining grinders were sold at 30% profit on the effective cost price. Find the overall profit percentage.

⚡ Shortcut Method

Purchase Cost = 600 × 1800 = ₹10,80,000

Effective CP = 10,80,000 + 36,000 + 24,000

= ₹11,40,000

Effective CP per Grinder

= 11,40,000 ÷ 600

= ₹1,900

SP of Damaged Grinders

= 30 × (1900 × 75%)

= ₹42,750

SP of Remaining Grinders

= 570 × (1900 × 130%)

= ₹14,07,900

Total SP

= 14,07,900 + 42,750

= ₹14,50,650

Profit

= 14,50,650 − 11,40,000

= ₹3,10,650

Profit %

= (3,10,650 ÷ 11,40,000) × 100

= 27.25%

✅ Final Answer

27.25% Profit

📌 Question 117

📝 Question

A wholesaler purchased 900 ceiling fans at ₹1,600 each. He spent ₹54,000 on freight and ₹36,000 on insurance. During transportation, 60 fans were damaged and sold at 55% of their effective cost price. The remaining fans were sold through an online marketplace that charged 8% commission on the selling price. If the wholesaler earned an overall profit of 15%, find the selling price of each good fan.

⚡ Shortcut Method

Purchase Cost = 900 × 1600 = ₹14,40,000

Effective CP = 14,40,000 + 54,000 + 36,000

= ₹15,30,000

Effective CP per Fan = 15,30,000 ÷ 900 = ₹1,700

Required Net SP = 15,30,000 × 115%

= ₹17,59,500

Recovery from Damaged Fans

= 60 × (1700 × 55%)

= ₹56,100

Net Amount Required from Good Fans

= 17,59,500 − 56,100

= ₹17,03,400

Let SP per Good Fan = ₹x

840 × 92% × x = 17,03,400

x = 17,03,400 ÷ (840 × 0.92)

= ₹2,204.97

✅ Final Answer

₹2,204.97 per fan


📌 Question 118

📝 Question

A retailer marks an article 250% above its cost price. During a festive sale, he offers successive discounts of 25%, 20%, and 10%. In addition, the customer receives a cashback equal to 10% of the final billed amount. Find the retailer’s overall profit percentage.

⚡ Shortcut Method

Assume CP = ₹100

MP = ₹350

Final SP

= 350 × 0.75 × 0.80 × 0.90 × 0.90

= ₹170.10

Profit

= 170.10 − 100

= ₹70.10

Profit %

= 70.10%

✅ Final Answer

70.10% Profit


📌 Question 119

📝 Question

A trader purchased 500 office chairs at ₹2,400 each. He spent ₹30,000 on transportation and ₹20,000 on packaging. During delivery, 25 chairs were damaged and sold at 40% of their effective cost price. The remaining chairs were sold at a 25% profit on the effective cost price, but the dealer paid 6% commission on the selling price to a marketing agency. Find the overall profit percentage.

⚡ Shortcut Method

Purchase Cost = 500 × 2400

= ₹12,00,000

Effective CP = 12,00,000 + 30,000 + 20,000

= ₹12,50,000

Effective CP per Chair

= 12,50,000 ÷ 500

= ₹2,500

Recovery from Damaged Chairs

= 25 × (2500 × 40%)

= ₹25,000

Net SP from Good Chairs

= 475 × (2500 × 125% × 94%)

= ₹13,96,562.50

Total Net SP

= 13,96,562.50 + 25,000

= ₹14,21,562.50

Profit

= 14,21,562.50 − 12,50,000

= ₹1,71,562.50

Profit %

= (1,71,562.50 ÷ 12,50,000) × 100

= 13.73%

✅ Final Answer

13.73% Profit


👑 Question 120

📝 Question

A mobile accessories distributor purchased 1,200 power banks at ₹900 each. He spent ₹48,000 on freight, ₹24,000 on insurance, and ₹18,000 on warehouse handling.

Out of the total stock:

  • 80 power banks were damaged and sold at 50% of their effective cost price.
  • 120 power banks were sold at cost price to clear old inventory.
  • The remaining power banks were sold through an e-commerce platform charging 10% commission on the selling price.

If the distributor earned an overall profit of 18%, find the selling price of each remaining power bank.

⚡ Shortcut Method

Purchase Cost = 1200 × 900

= ₹10,80,000

Effective CP = 10,80,000 + 48,000 + 24,000 + 18,000

= ₹11,70,000

Effective CP per Power Bank

= 11,70,000 ÷ 1200

= ₹975

Required Net SP

= 11,70,000 × 118%

= ₹13,80,600

Recovery from Damaged Stock

= 80 × (975 × 50%)

= ₹39,000

Recovery from Cost Price Stock

= 120 × 975

= ₹1,17,000

Net Amount Required from Remaining Stock

= 13,80,600 − 39,000 − 1,17,000

= ₹12,24,600

Let SP per Remaining Power Bank = ₹x

1000 × 90% × x = 12,24,600

900x = 12,24,600

x = ₹1,360.67

✅ Final Answer

₹1,360.67 per power bank

📖 Previous Parts

💡 Shortcut Trick of the Day

Use Effective Cost Price First

Whenever transportation, insurance, packaging, freight, handling charges, or loading expenses are mentioned:

✅ First calculate the Effective Cost Price (ECP)

Effective Cost Price = Purchase Cost + All Additional Expenses

Then solve the question using the effective cost instead of the original purchase cost.

This shortcut eliminates mistakes and saves valuable exam time.

🚀 Banking Exam Speed Tips

  • ⚡ Convert percentages into multiplication factors whenever possible.
  • ⚡ Memorize common percentage equivalents like 12.5%, 16⅔%, 25%, 33⅓%, 37.5%, 62.5%, and 66⅔%.
  • ⚡ Calculate the Effective Cost Price before starting the solution.
  • ⚡ Use reverse calculations when the final selling price is given.
  • ⚡ Practice solving questions mentally before writing calculations.
  • ⚡ Focus on identifying the concept first, then perform the arithmetic.

🎯 Challenge Question

A wholesaler purchased 800 induction cooktops at ₹2,200 each. He spent ₹80,000 on transportation and ₹40,000 on insurance.

Out of the total stock:

  • 50 cooktops were damaged and sold at 40% of their effective cost price.
  • 100 cooktops were sold at 8% loss during clearance.
  • The remaining cooktops were sold through an online platform charging 6% commission on the selling price.

If the wholesaler earned an overall profit of 18%, find the selling price of each remaining cooktop.

🏆 Can you solve it without using a calculator?

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